(\sin^{-1}\left\(\frac{1}{\sqrt{2}}\right\)) का मान क्या है?
What is the value of (\sin^{-1}\left\(\frac{1}{\sqrt{2}}\right\))?
Explanation opens after your attempt
Correct Answer
A. \(\frac{\pi}{4}\)
Concept
Because \(\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}\). Standard angle values are very useful in exams.
Why this answer is correct
The correct answer is A. \(\frac{\pi}{4}\). Because \(\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}\). Standard angle values are very useful in exams.
Exam Tip
क्योंकि \(\sin\frac{\pi}{4}=\frac{1}{\sqrt{2}}\) है। मानक कोणों के मान परीक्षा में बहुत उपयोगी होते हैं।
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