\(\tan^{-1}\sqrt{3}\) का प्रधान मान क्या है?
What is the principal value of \(\tan^{-1}\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{\pi}{3}\)
Concept
Because \(\tan\frac{\pi}{3}=\sqrt{3}\) and \(\frac{\pi}{3}\) lies in the principal range. For \(\tan^{-1}\), take the angle in (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).
Why this answer is correct
The correct answer is A. \(\frac{\pi}{3}\). Because \(\tan\frac{\pi}{3}=\sqrt{3}\) and \(\frac{\pi}{3}\) lies in the principal range. For \(\tan^{-1}\), take the angle in (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)).
Exam Tip
क्योंकि \(\tan\frac{\pi}{3}=\sqrt{3}\) है और \(\frac{\pi}{3}\) प्रधान सीमा में है। \(\tan^{-1}\) में कोण (\left\(-\frac{\pi}{2},\frac{\pi}{2}\right\)) में लें।
Login to save your score, XP, coins and progress.