यदि \(\sin^{-1}x=\frac{\pi}{6}\) हो तो (x) का मान क्या है?

If \(\sin^{-1}x=\frac{\pi}{6}\), what is the value of (x)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\)

Step 1

Concept

Taking \(\sin\) on both sides gives \(x=\sin\frac{\pi}{6}=\frac{1}{2}\). In inverse functions convert the angle back to the original value.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\). Taking \(\sin\) on both sides gives \(x=\sin\frac{\pi}{6}=\frac{1}{2}\). In inverse functions convert the angle back to the original value.

Step 3

Exam Tip

दोनों तरफ \(\sin\) लेने पर \(x=\sin\frac{\pi}{6}=\frac{1}{2}\) मिलता है। उल्टे फलन में कोण से मूल मान निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\sin^{-1}x=\frac{\pi}{6}\) हो तो (x) का मान क्या है? / If \(\sin^{-1}x=\frac{\pi}{6}\), what is the value of (x)?

Correct Answer: A. \(\frac{1}{2}\). Explanation: दोनों तरफ \(\sin\) लेने पर \(x=\sin\frac{\pi}{6}=\frac{1}{2}\) मिलता है। उल्टे फलन में कोण से मूल मान निकालें। / Taking \(\sin\) on both sides gives \(x=\sin\frac{\pi}{6}=\frac{1}{2}\). In inverse functions convert the angle back to the original value.

Which concept should I revise for this Mathematics MCQ?

Taking \(\sin\) on both sides gives \(x=\sin\frac{\pi}{6}=\frac{1}{2}\). In inverse functions convert the angle back to the original value.

What exam hint can help solve this Mathematics question?

दोनों तरफ \(\sin\) लेने पर \(x=\sin\frac{\pi}{6}=\frac{1}{2}\) मिलता है। उल्टे फलन में कोण से मूल मान निकालें।