किसी विलयन के लिए \(\Delta T_b=0.208,K\), \(K_b=0.52,K,kg,mol^{-1}\) और \(i=2\) है। विलयन की मोललता क्या होगी?
For a solution, \(\Delta T_b=0.208,K\), \(K_b=0.52,K,kg,mol^{-1}\), and \(i=2\). What is the molality of the solution?
Explanation opens after your attempt
B. (0.2,m)
Concept
\(\Delta T_b=iK_bm\) से \(m=\frac{\Delta T_b}{iK_b}\) होगा। / From \(\Delta T_b=iK_bm\), \(m=\frac{\Delta T_b}{iK_b}\).
Why this answer is correct
\(m=\frac{0.208}{2\times0.52}=0.2,m\)। / \(m=\frac{0.208}{2\times0.52}=0.2,m\).
Exam Tip
जब (i) दिया हो तो उसे हर में शामिल करें। / When (i) is given, include it in the denominator.
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