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In this Class 12 Chemistry topic from Chapter 01: Solutions, students learn how vapour pressure arises from the dynamic equilibrium between evaporation and condensation in a liquid. The topic explains the effect of temperature and the presence of a non-volatile solute, including lowering of vapour pressure. Students also connect vapour pressure with mole fraction through Raoult’s law and examine how ideal and non-ideal solutions differ, using equations and basic numerical applications.
TOPIC PRACTICE
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Vapour pressure
Osmotic pressure
Atmospheric pressure
Internal pressure
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It increases
It decreases
It becomes zero
It always remains constant
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Number of solvent particles at the surface decreases
Number of solvent particles at the surface increases
The solute itself forms more vapour
The liquid immediately becomes a gas
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Mole fraction of the solvent
Colour of the solute
Shape of the container
Smell of the solution
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P = X_solvent × P°
P = X_solute + P°
P = P° / X_solvent
P = X_solvent − P°
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Lower vapour pressure
Higher vapour pressure
Always the same vapour pressure
Infinite vapour pressure
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The fraction of water molecules available at the surface decreases
Sugar is more volatile than water
The water temperature suddenly becomes zero
All attraction disappears from the solution
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A closed container
An open field
A porous container
Flowing water
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More volatile
Less volatile
Always a solid
Completely non-volatile
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Low
High
Always zero
Infinite
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High
Low
Zero
Independent of temperature
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When the liquid vapour pressure becomes equal to external pressure
When the colour of the liquid changes
When the mass of the liquid becomes zero
When the container cannot be opened
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Its vapour pressure is lower at the same temperature
Its vapour pressure is always infinite
It never forms vapour
It has no particles
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Because its vapour pressure decreases
Because its vapour pressure becomes infinite
Because the solute escapes as vapour
Because the solvent disappears
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Lower
Higher
Exactly the same
Infinite
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The vapour pressure of the pure solvent
The mass of the solute
The colour of the solution
The volume of the container
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Mole fraction of the solvent
Temperature of the solute
Pressure only
Colour of the vapour
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It decreases
It increases
It remains zero
It immediately doubles
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Colligative property
Colour-dependent property
Shape-dependent property
Odour-dependent property
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The one with more non-volatile solute particles
The one containing only pure solvent
The one with no solute
The one with a larger container but no solute
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Vapour pressure decreases further
Vapour pressure increases
Vapour pressure becomes infinite
Vapour pressure becomes independent of external pressure
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Evaporation
Freezing
Condensation
Solution formation
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Rates of evaporation and condensation
Rates of dissolution and freezing
Rates of boiling and melting
Rates of colour and odour change
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Nature of liquid and temperature
Colour of container
Length of liquid name
Person measuring it
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Because its particles easily become vapour
Because its particles do not move at all
Because it has no surface
Because it is always solid
Question 1EasyLevel 1
What is the pressure exerted by vapour above a liquid in a closed container called?
Correct answer: A
In a closed container, some liquid molecules escape from the surface and form vapour. After dynamic equilibrium is reached, the vapour molecules collide with the container and liquid surface, exerting a pressure at that temperature. This equilibrium pressure is called vapour pressure. Osmotic pressure concerns solvent flow through a semipermeable membrane, not vapour above a liquid.
How does the vapour pressure of a liquid generally change when its temperature is increased?
Correct answer: A
When temperature rises, the average kinetic energy of liquid molecules increases. Consequently, more molecules acquire enough energy to escape from the liquid surface and enter the vapour phase. This increases the number of vapour molecules above the liquid and therefore raises the equilibrium vapour pressure. It does not become zero or remain constant under ordinary conditions.
Why does the vapour pressure of a solvent decrease when a non-volatile solute is added?
Correct answer: A
A non-volatile solute has negligible vapour pressure and does not escape appreciably into the gas phase. Its presence lowers the mole fraction and availability of solvent molecules at the surface. Thus fewer solvent molecules evaporate, so the solvent vapour pressure becomes lower than that of the pure solvent.
According to Raoult's law, the vapour pressure of a solvent in a solution is proportional to what?
Correct answer: A
For an ideal solution containing a non-volatile solute, Raoult's law is written as P_solvent = X_solvent P°_solvent. At fixed temperature, the pure-solvent pressure P° is constant, so the solution vapour pressure is directly proportional to the solvent mole fraction. Colour, container shape, and smell do not appear in this relation.
Which is the correct simple form of Raoult's law for the vapour pressure of a solvent in a solution?
Correct answer: A
For a solution containing a non-volatile solute, Raoult’s law states that the partial vapour pressure of the solvent is P = X_solvent P°. Here, X_solvent is the mole fraction of the solvent and P° is the vapour pressure of the pure solvent at the same temperature. Thus multiplication is required; the addition, subtraction, and division forms are incorrect.
Compared with the pure solvent, what vapour pressure does a solution containing a non-volatile solute have?
Correct answer: A
A non-volatile solute has negligible vapour pressure of its own, so it does not significantly enter the vapour phase. Its presence reduces the mole fraction of the solvent and decreases the number of solvent molecules escaping from the surface. By Raoult’s law, P_solution = X_solvent P°; because X_solvent is less than 1, the solution vapour pressure is lower than P°.
What is the main reason for lowering of vapour pressure when sugar is dissolved in water?
Correct answer: A
Dissolved sugar is treated as a non-volatile solute under ordinary conditions. It occupies part of the solution and reduces the mole fraction of water, so fewer water molecules are available to escape per unit surface in equilibrium. Consequently, water's vapour pressure falls. Sugar is not more volatile, and attractions do not disappear.
In what type of container can vapour pressure be measured properly?
Correct answer: A
Vapour pressure is the pressure exerted by vapour in equilibrium with its liquid at a specified temperature. A closed container is needed so that vapour can accumulate and condensation can balance evaporation. In an open or porous container, vapour escapes continuously, so a stable equilibrium pressure cannot normally be established or measured.
If a liquid has a high vapour pressure, what is it generally like?
Correct answer: A
Vapour pressure measures the tendency of molecules to escape from a liquid and exist in the vapour phase at a given temperature. A high vapour pressure means that many molecules can escape relatively easily. Such a liquid is called more volatile and usually evaporates readily. A low vapour pressure indicates stronger resistance to escape and lower volatility, not higher volatility.
If intermolecular attraction in a liquid is strong, how will its vapour pressure generally be?
Correct answer: A
Strong intermolecular attraction holds molecules more firmly in the liquid phase. At a given temperature, fewer molecules possess enough energy to escape into the vapour phase, so the equilibrium vapour pressure is lower. The pressure is not necessarily zero, because some molecules can still escape; “low,” rather than “always zero,” is the correct conclusion.
If intermolecular attractions in a liquid are weak, how will its vapour pressure generally be?
Correct answer: A
Intermolecular attractions hold liquid molecules together. When these attractions are weak, a molecule needs less energy to leave the liquid surface and enter the vapour phase. Therefore, at the same temperature, more molecules escape and the equilibrium vapour pressure is generally higher. Strong attractions would make escape more difficult and usually produce lower vapour pressure.
Boiling occurs throughout the liquid when vapour bubbles can form and persist. This becomes possible when the liquid's vapour pressure equals the pressure exerted by the surroundings. Surface evaporation can occur below this condition, so merely seeing vapour or using an open container does not define boiling. Colour and mass are not the criterion.
What can be one reason for a liquid having a higher boiling point?
Correct answer: A
A liquid boils when its vapour pressure reaches the external pressure. If its vapour pressure is lower than that of another liquid at the same temperature, it must be heated more to reach the same external pressure, giving a higher boiling point. The liquid still forms vapour; infinite pressure and absence of particles are impossible claims.
Why does the boiling point of a solution increase when a non-volatile solute is added?
Correct answer: A
A non-volatile solute lowers the solvent mole fraction and therefore lowers the solution vapour pressure at a given temperature. The solution must then be heated to a higher temperature before its vapour pressure equals the external pressure. That higher temperature is the elevated boiling point. The solute is not the component escaping as vapour.
Compared with pure water, how will the vapour pressure of salt water be?
Correct answer: A
Dissolved salt is treated as a non-volatile solute in this context. It contributes particles to the liquid phase but not appreciable vapour, reducing the mole fraction and escaping tendency of water. Thus, at the same temperature, salt water has a lower vapour pressure than pure water. The amount of lowering depends on solution concentration.
In Raoult’s law, the symbol P° denotes the vapour pressure of the pure solvent at the specified temperature. The vapour pressure of the solvent in the solution is written as P = X_solvent P°. Since the solvent mole fraction is normally below one after adding solute, the solution pressure is usually lower than P°. P° is not a mass, colour, or container-volume quantity.
The symbol X_solvent denotes the mole fraction of the solvent, calculated as moles of solvent divided by total moles of all components in the solution. In Raoult's law, decreasing this fraction decreases the solvent's partial vapour pressure at fixed temperature. It is not a temperature, pressure-only, or colour symbol.
If the mole fraction of the solvent decreases, what happens to its vapour pressure according to Raoult's law?
Correct answer: A
Raoult's law gives P_solvent = X_solvent P°_solvent. At constant temperature, P°_solvent is fixed, so the solvent pressure changes in the same direction as X_solvent. A decrease in mole fraction therefore causes a proportional decrease in vapour pressure. The result is not automatically zero or double; the amount of change depends on the numerical change in X.
Lowering of vapour pressure is what type of property?
Correct answer: A
A colligative property depends primarily on the number of dissolved solute particles, not on their chemical identity, under the stated ideal conditions. Lowering of vapour pressure is one such property. For electrolytes, dissociation changes the effective particle number, but colour, shape and odour do not define the effect.
Which solution will show greater lowering of vapour pressure?
Correct answer: A
For comparable solutions at the same temperature, lowering of vapour pressure is governed by the number of non-volatile solute particles. More such particles produce a larger solute mole fraction and a larger relative lowering. Pure solvent and a solute-free sample show no solute-caused lowering; container size alone is irrelevant.
If more non-volatile solute is added to a solution, what happens to vapour pressure?
Correct answer: A
Adding more non-volatile solute increases the solute mole fraction and decreases the solvent mole fraction. From p = x_solvent p° at constant temperature, the solvent vapour pressure therefore falls further. The effect is not an increase or infinity; the option about external pressure is also unrelated to this concentration change.
What is the process of vapour formation from the surface of a pure liquid called?
Correct answer: A
Evaporation is the process in which molecules escape from the surface of a liquid and enter the vapour phase. It can occur below the boiling point because some surface molecules possess enough kinetic energy to escape. Freezing changes a liquid into a solid, condensation changes vapour into liquid, and solution formation refers to mixing substances rather than surface vapour formation.
In a closed container, which rates become equal when equilibrium is established between liquid and vapour?
Correct answer: A
In a closed vessel, molecules continuously leave the liquid by evaporation and return from vapour by condensation. At dynamic equilibrium, these opposite rates become equal, so the amounts of liquid and vapour and the pressure remain constant. The processes in the other options are not the paired phase changes defining vapour equilibrium.
At equilibrium, vapour pressure is determined mainly by temperature and the nature of the liquid, which includes the strength of intermolecular attractions. Heating changes molecular energies, while different liquids have different escape tendencies. Container colour, word length and the observer do not determine the thermodynamic vapour pressure.
Why does a liquid with higher vapour pressure evaporate faster at the same temperature?
Correct answer: A
At a fixed temperature, higher vapour pressure indicates a greater equilibrium tendency for molecules to occupy the vapour phase. This usually reflects weaker effective intermolecular attraction or greater volatility, so surface molecules escape more readily and evaporation is faster. The other statements contradict the molecular picture of a liquid.
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