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Subjects

Chemistry

6: Molar Mass Determination

मोलर द्रव्यमान का निर्धारण

In this Class 12 Chemistry topic from Chapter 01: Solutions, students learn how the molar mass of a solute can be determined from the measurable properties of a solution. The topic connects mass, moles, concentration, and colligative properties such as relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, and osmotic pressure. Students also practise selecting suitable formulas, interpreting experimental data, and recognising how observed results can indicate association or dissociation of solute particles.

TOPIC PRACTICE

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Up to 12 questions from this page. Select your focus, then start.

12 questions

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Medium · Level 9
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  1. 60 g mol⁻¹
  2. 40 g mol⁻¹
  3. 30 g mol⁻¹
  4. 20 g mol⁻¹
Medium · Level 9
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  1. (p⁰ − p)/p⁰ = w₂M₁/(w₁M₂)
  2. (p⁰ − p)/p⁰ = w₁M₂/(w₂M₁)
  3. (p⁰ − p)/p⁰ = M₁M₂/(w₁w₂)
  4. (p⁰ − p)/p⁰ = w₁w₂M₁M₂
Medium · Level 9
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  1. Its molar mass may be lower
  2. Its molar mass must be higher
  3. It contains no solute
  4. Its temperature is zero
Medium · Level 9
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  1. Whether the solution is sufficiently dilute, completely dissolved, and homogeneous
  2. Whether the solvent has a dark colour
  3. Whether the container is made of glass
  4. Whether the solute is shiny
Medium · Level 9
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  1. Dissociation
  2. Association
  3. Complete ionisation
  4. Evaporation of the solvent
Medium · Level 9
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  1. Osmotic pressure
  2. Elevation in boiling point
  3. Relative lowering of vapour pressure
  4. Depression in freezing point
Medium · Level 9
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  1. It will be higher
  2. It will be lower
  3. It will remain unchanged
  4. It will become zero
Medium · Level 9
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  1. The molar mass will be higher
  2. The molar mass will be lower
  3. There will be no effect
  4. The molar mass will become negative
Medium · Level 9
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  1. The calculated value may be wrong because the actual pure-solute amount differs
  2. There will be no effect
  3. The molar mass will always be exact
  4. The osmotic pressure will become zero
Medium · Level 9
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  1. Because interparticle interactions are no longer negligible
  2. Because temperature disappears
  3. Because solvent mass is always zero
  4. Because solute becomes colourless
Medium · Level 9
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  1. It can indicate abnormality such as association or dissociation
  2. It necessarily changes the solvent
  3. It converts molar mass into colour
  4. It makes temperature irrelevant
Medium · Level 9
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  1. First check method, given quantities, unit conversion, and need for i
  2. Directly write any formula
  3. Keep all temperatures in Celsius
  4. Interchange solute and solvent masses

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