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Subjects

Chemistry

6: Molar Mass Determination

मोलर द्रव्यमान का निर्धारण

In this Class 12 Chemistry topic from Chapter 01: Solutions, students learn how the molar mass of a solute can be determined from the measurable properties of a solution. The topic connects mass, moles, concentration, and colligative properties such as relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, and osmotic pressure. Students also practise selecting suitable formulas, interpreting experimental data, and recognising how observed results can indicate association or dissociation of solute particles.

TOPIC PRACTICE

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Up to 25 questions from this page. Select your focus, then start.

25 questions

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Easy · Level 3
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  1. 0.4 K
  2. −0.4 K
  3. 4.0 K
  4. 273 K
Easy · Level 3
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  1. 0.25 kg
  2. 0.025 kg
  3. 2.5 kg
  4. 25 kg
Easy · Level 3
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  1. 0.2 mol kg⁻¹
  2. 0.05 mol kg⁻¹
  3. 0.5 mol kg⁻¹
  4. 5 mol kg⁻¹
Easy · Level 3
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  1. Molar mass of the solute
  2. Molar mass of the solvent
  3. Temperature of the solution
  4. Colour of the solution
Easy · Level 3
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  1. Fewer
  2. More
  3. The same
  4. Zero
Easy · Level 3
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  1. The solute with lower molar mass
  2. The solute with higher molar mass
  3. The solute with darker colour
  4. The solute with stronger smell
Easy · Level 3
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  1. Relative lowering of vapour pressure
  2. Colour of the solution
  3. Hardness of the solute
  4. Volume of the container in every case
Easy · Level 3
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  1. The result may be incorrect
  2. The result will always be correct
  3. The molar mass will become zero
  4. Temperature measurement will no longer be needed
Easy · Level 3
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  1. To calculate the temperature difference from that of the solution
  2. To observe the colour of the solvent
  3. To identify the name of the solute
  4. To determine the mass of the container
Easy · Level 3
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  1. 0
  2. 1 K
  3. 273 K
  4. −1 K
Easy · Level 3
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  1. Elevation in boiling point
  2. Depression in freezing point
  3. Osmotic pressure
  4. Diffusion
Easy · Level 3
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  1. Depression in freezing point
  2. Elevation in boiling point
  3. Osmotic pressure
  4. Evaporation
Easy · Level 3
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  1. w/M
  2. M/w
  3. wM
  4. w + M
Easy · Level 3
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  1. Mass of solute
  2. Colour of solute
  3. Colour of container
  4. Name of laboratory
Easy · Level 3
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  1. Effective number of solute particles
  2. Colour of solute
  3. Shape of container
  4. Smell of solution
Easy · Level 3
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  1. Difference between the freezing points of the solution and pure solvent
  2. Colour of the solution
  3. Odour of the solvent
  4. Height of the container
Easy · Level 3
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  1. Decrease in the boiling point of the solution
  2. Difference between the boiling points of the solution and the pure solvent
  3. Mass of the solvent
  4. Volume of the solute
Easy · Level 3
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  1. Because osmotic pressure can be measured at room temperature even for dilute solutions
  2. Because solvent is not needed
  3. Because only colour is observed
  4. Because it applies only to gases
Easy · Level 3
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  1. Fewer
  2. More
  3. Unchanged
  4. Equal to the molar mass
Easy · Level 3
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  1. m = ΔTf/Kf
  2. m = ΔTfKf
  3. m = Kf/(ΔTf)²
  4. m = Kf + ΔTf
Easy · Level 3
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  1. ΔTb = Kb m
  2. ΔTb = m/Kb
  3. ΔTb = Kb + m
  4. ΔTb = Kb − m
Easy · Level 3
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  1. Determining molar mass from freezing-point depression
  2. Measuring the hardness of a metal
  3. Identifying the colour of a gas
  4. Reducing the electrical conductivity of water
Easy · Level 3
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  1. The measurement error may be large
  2. The solute always burns
  3. The solvent never solidifies
  4. The molar mass always becomes zero
Easy · Level 3
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  1. Molality
  2. Colour
  3. Odour
  4. The name of a pressure
Easy · Level 3
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  1. m = ΔTb / Kb
  2. m = Kb × ΔTb
  3. m = Kb − ΔTb
  4. m = Kb / (ΔTb)²

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