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In this Class 12 Chemistry topic from Chapter 01: Solutions, students learn how the molar mass of a solute can be determined from the measurable properties of a solution. The topic connects mass, moles, concentration, and colligative properties such as relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, and osmotic pressure. Students also practise selecting suitable formulas, interpreting experimental data, and recognising how observed results can indicate association or dissociation of solute particles.
TOPIC PRACTICE
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Up to 25 questions from this page. Select your focus, then start.
25 questions
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Easy · Level 3View options
0.4 K
−0.4 K
4.0 K
273 K
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0.25 kg
0.025 kg
2.5 kg
25 kg
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0.2 mol kg⁻¹
0.05 mol kg⁻¹
0.5 mol kg⁻¹
5 mol kg⁻¹
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Molar mass of the solute
Molar mass of the solvent
Temperature of the solution
Colour of the solution
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Fewer
More
The same
Zero
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The solute with lower molar mass
The solute with higher molar mass
The solute with darker colour
The solute with stronger smell
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Relative lowering of vapour pressure
Colour of the solution
Hardness of the solute
Volume of the container in every case
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The result may be incorrect
The result will always be correct
The molar mass will become zero
Temperature measurement will no longer be needed
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To calculate the temperature difference from that of the solution
To observe the colour of the solvent
To identify the name of the solute
To determine the mass of the container
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0
1 K
273 K
−1 K
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Elevation in boiling point
Depression in freezing point
Osmotic pressure
Diffusion
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Depression in freezing point
Elevation in boiling point
Osmotic pressure
Evaporation
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w/M
M/w
wM
w + M
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Mass of solute
Colour of solute
Colour of container
Name of laboratory
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Effective number of solute particles
Colour of solute
Shape of container
Smell of solution
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Difference between the freezing points of the solution and pure solvent
Colour of the solution
Odour of the solvent
Height of the container
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Decrease in the boiling point of the solution
Difference between the boiling points of the solution and the pure solvent
Mass of the solvent
Volume of the solute
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Because osmotic pressure can be measured at room temperature even for dilute solutions
Because solvent is not needed
Because only colour is observed
Because it applies only to gases
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Fewer
More
Unchanged
Equal to the molar mass
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m = ΔTf/Kf
m = ΔTfKf
m = Kf/(ΔTf)²
m = Kf + ΔTf
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ΔTb = Kb m
ΔTb = m/Kb
ΔTb = Kb + m
ΔTb = Kb − m
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Determining molar mass from freezing-point depression
Measuring the hardness of a metal
Identifying the colour of a gas
Reducing the electrical conductivity of water
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The measurement error may be large
The solute always burns
The solvent never solidifies
The molar mass always becomes zero
Easy · Level 3View options
Molality
Colour
Odour
The name of a pressure
Easy · Level 3View options
m = ΔTb / Kb
m = Kb × ΔTb
m = Kb − ΔTb
m = Kb / (ΔTb)²
Question 1EasyLevel 3
A solution freezes at −0.4 °C, while pure water freezes at 0 °C. What is ΔT_f?
Correct answer: A
Freezing-point depression is defined as ΔT_f = T_f° − T_f, where T_f° is the freezing point of the pure solvent and T_f is the freezing point of the solution. Thus, ΔT_f = 0 − (−0.4) = 0.4 °C. Since a temperature difference has the same numerical value in Celsius and kelvin, the depression is 0.4 K. Therefore, option A is correct.
If 5 g of solute is dissolved in 250 g of solvent, what is the mass of the solvent in kilograms?
Correct answer: A
The mass of solvent is given as 250 g. To convert grams to kilograms, divide by 1000 because 1000 g = 1 kg. Therefore, mass of solvent = 250/1000 = 0.25 kg. The solute mass is not used for this particular conversion. Hence, 0.25 kg is the correct answer, and option A is unambiguous.
If 0.1 mol of solute is dissolved in 0.5 kg of solvent, what is the molality?
Correct answer: A
Molality is defined as the number of moles of solute divided by the mass of solvent in kilograms: m = moles of solute / kilograms of solvent. Substituting the data gives m = 0.1/0.5 = 0.2 mol kg⁻¹. The mass of the solution is not used; only the mass of the solvent is required. Therefore, option A is the correct answer.
In molar mass determination, what does M_B generally represent?
Correct answer: A
In the usual notation for a binary solution, A denotes the solvent and B denotes the solute. Therefore, M_B means the molar mass of component B, which is the solute. This quantity is used in formulas involving mole fraction, molality, and colligative-property methods for determining molar mass. The other options describe unrelated physical quantities.
If a solute has a higher molar mass, how many moles will be present in the same mass?
Correct answer: A
The number of moles is calculated using n = m/M, where m is the given mass and M is the molar mass. When the mass is kept constant, increasing M makes n smaller because moles and molar mass are inversely proportional. Thus, a solute with greater molar mass contributes fewer moles in the same mass. Zero moles would occur only if the mass were zero.
If equal masses of two solutes are taken, which solute will produce the greater colligative effect, assuming the same solvent and no association or dissociation?
Correct answer: A
For a fixed mass, the number of moles is n = w/M. A lower molar mass therefore gives a larger number of moles and hence more dissolved particles. Colligative properties depend on the number of solute particles, not on their colour, smell, or chemical identity alone. Consequently, the lower-molar-mass solute produces the greater effect when both solutions are otherwise comparable.
While determining molar mass from lowering of vapour pressure, which quantity is directly related to the mole fraction of a non-volatile solute?
Correct answer: A
For a solution containing a non-volatile solute, Raoult’s law gives the relative lowering of vapour pressure as (p° − p)/p° = x_B, where x_B is the solute mole fraction in the dilute-solution approximation. This measurable pressure change helps determine the amount of solute and therefore its molar mass. Colour, hardness, and container volume are not the relevant quantities.
If the solute is not completely dissolved during molar mass determination, what may happen to the result?
Correct answer: A
Colligative properties depend on the number of particles actually present in solution. If some solute remains undissolved, the measured solution contains fewer dissolved particles than expected from the weighed mass. The observed temperature or vapour-pressure change will therefore not correspond to the assumed amount, producing an erroneous calculated molar mass. Complete dissolution and proper mixing are essential experimental precautions.
Why is the temperature of the pure solvent measured in molar mass determination?
Correct answer: A
Colligative methods such as elevation of boiling point and depression of freezing point use a temperature difference: ΔT_b = T_b(solution) − T_b° or ΔT_f = T_f° − T_f(solution). The pure-solvent temperature provides the reference value against which the solution temperature is compared. Without this reference, the magnitude of the colligative change and the subsequent molar-mass calculation cannot be obtained accurately.
If the freezing point of the pure solvent and the solution are equal, what is ΔT_f?
Correct answer: A
Freezing-point depression is defined as ΔT_f = T_f° − T_f, where T_f° is the freezing point of the pure solvent and T_f is the freezing point of the solution. If both temperatures are equal, their difference is zero. Thus, ΔT_f = 0 K. A value of −1 K would imply that the two temperatures differ by one kelvin, which is not stated.
If the boiling point of a solution is higher than that of the pure solvent, which colligative property does this represent?
Correct answer: A
A non-volatile solute lowers the vapour pressure of a solvent. Consequently, the solution must be heated to a higher temperature to reach the external pressure required for boiling. The increase in boiling temperature is called elevation in boiling point and is represented by ΔT_b. It is a colligative property because its magnitude depends primarily on the number of dissolved solute particles.
If the freezing point of a solution is lower than that of the pure solvent, which colligative property does this represent?
Correct answer: A
When a suitable non-volatile solute is dissolved, the chemical potential of the liquid solvent decreases, so the solution freezes at a lower temperature than the pure solvent. This decrease is called depression in freezing point and is written as ΔT_f = T_f° − T_f. It is a colligative property and can be used, through the appropriate formula, to determine the solute’s molar mass.
If the mass of a solute is w and its molar mass is M, how is the number of moles of solute written?
Correct answer: A
The definition of molar mass is M = w/n, where w is the mass of the substance and n is its amount in moles. Rearranging this expression gives n = w/M. Therefore, the number of moles is obtained by dividing mass by molar mass. If w is in grams and M is in grams per mole, the resulting unit is mole, confirming that option A is dimensionally correct.
In molar mass determination, which basic information is needed first?
Correct answer: A
Molar mass is calculated from the amount of substance and its mass, using the relation M = m/n. Therefore, measuring the mass of the solute accurately is an essential first step in an experimental determination. The colour of the solute, the colour of the container, and the laboratory name do not enter the calculation and cannot help determine molar mass. Thus, option A is correct.
What is most important while determining molar mass using colligative properties?
Correct answer: A
All colligative properties depend on the effective number of dissolved solute particles. During molar-mass determination, dissociation or association can change this number and may produce an abnormal observed molar mass. Therefore, the effective particle count must be considered carefully, often through the van’t Hoff factor. Colour, container shape, and smell are not controlling factors. Option A is correct.
Which measurement is needed to determine molar mass by the freezing-point depression method?
Correct answer: A
The freezing-point depression is represented by ΔTf = Tf° − Tf, where Tf° is the freezing point of the pure solvent and Tf is the freezing point of the solution. Using ΔTf = Kf m for a nonelectrolyte, the solution molality can be calculated; with the known solute mass and solvent mass, its molar mass follows. Hence option A is required.
What is the correct meaning of ΔTb in the boiling-point elevation method?
Correct answer: B
For a solution containing a non-volatile solute, the solvent vapour pressure is lowered. The solution must therefore be heated to a higher temperature before its vapour pressure equals the external pressure. The boiling-point elevation is ΔTb = Tb(solution) − Tb(pure solvent), a positive difference. Thus option B is correct, while option A describes the opposite effect.
Why is the osmotic-pressure method more useful for substances with high molar mass?
Correct answer: A
High-molar-mass substances such as proteins and polymers often dissolve only in very dilute solutions and may decompose when heated. Osmotic pressure follows π = CRT and can be measured at or near room temperature, so even a small concentration produces a measurable property. This avoids heating and is suitable for macromolecules. Therefore, option A is correct.
If the actual molar mass of a solute is high, how many moles will be present for the same dissolved mass?
Correct answer: A
The number of moles is calculated by n = m/M, where m is the given mass and M is the molar mass. When the mass remains fixed, increasing M makes the quotient smaller. Thus a high-molar-mass substance contributes fewer moles than a low-molar-mass substance of the same mass. The number of moles is not unchanged and cannot be equal to molar mass. Option A is correct.
Which relation is correct for finding molality in the freezing-point depression method?
Correct answer: A
For a nonelectrolyte, the depression in freezing point is related to molality by ΔTf = Kf m, where Kf is the cryoscopic constant of the solvent. Rearranging this equation by dividing both sides by Kf gives m = ΔTf/Kf. The other options use incorrect multiplication, powers, or addition and are dimensionally inconsistent. Therefore, option A is correct.
Which relation is correct for a nonelectrolyte in the boiling-point elevation method?
Correct answer: A
For a dilute solution containing a nonelectrolyte, the elevation in boiling point is directly proportional to the molality of the solution. The relation is ΔTb = Kb m, where Kb is the ebullioscopic constant of the solvent and m is molality. It is not a quotient, sum, or difference. Hence option A is the correct relation used in calculations.
The Rast method is mainly related to which purpose?
Correct answer: A
The Rast method is a cryoscopic method used to determine the molar mass of a solute. In this method, the solute is dissolved in a suitable solvent, commonly camphor in the classical procedure, and the depression in the solvent’s freezing point is measured. Using the freezing-point relation, the molar mass is calculated. Therefore, option A is correct.
If ΔTf is very small while determining molar mass, what is the main experimental problem?
Correct answer: A
When the freezing-point depression, ΔTf, is very small, it is difficult to measure the temperature difference with high precision. A small absolute error then represents a large relative error. Since the calculated molar mass depends on ΔTf, this uncertainty can significantly affect the final result. Therefore, the main problem is increased measurement error, making option A correct.
If Kf and ΔTf are given, which quantity can be found first?
Correct answer: A
For a nonelectrolyte solution, the freezing-point depression relation is ΔTf = Kf m, where Kf is the cryoscopic constant and m is molality. Rearranging gives m = ΔTf / Kf. Thus, the given values directly provide the molality first; quantities such as moles and molar mass may be calculated afterward if additional data are supplied. Hence, option A is correct.
If Kb and ΔTb are given, how is molality found for a nonelectrolyte?
Correct answer: A
For a dilute nonelectrolyte solution, the elevation in boiling point is given by ΔTb = Kb m, where Kb is the ebullioscopic constant and m is the molality. Dividing both sides by Kb gives m = ΔTb / Kb. Therefore, the boiling-point data first yield molality through option A; the other expressions do not follow from the colligative-property equation.
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