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In this Class 12 Chemistry topic from Chapter 01: Solutions, students learn how the physical properties of a solution depend on the number of dissolved solute particles rather than their chemical identity. The topic explains lowering of vapour pressure, elevation of boiling point, depression of freezing point and osmotic pressure. Students also apply colligative-property equations to calculate molar mass, understand dilute solutions, and use the van’t Hoff factor to interpret association or dissociation of solute particles.
TOPIC PRACTICE
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Easy · Level 3View options
Water enters the cell and it swells
Water leaves the cell and it shrinks
No change occurs
Salt turns into gas inside the cell
Easy · Level 3View options
The vapour pressure of the solution decreases.
The colour of the solute changes.
The mass of the solvent becomes zero.
Gravitational force disappears in the solution.
Easy · Level 3View options
Urea
NaCl
MgCl₂
Glucose
Easy · Level 3View options
0.25 m
0.50 m
1.00 m
1.86 m
Easy · Level 3View options
25% greater
Equal to 75% of it
Double
Triple
Easy · Level 3View options
Viscosity
Surface tension
Osmotic pressure
Refractive index
Easy · Level 3View options
Because it depends on the colour of the solution
Because it depends on the number of solute particles, not their nature
Because it occurs only in gases
Because it occurs only with a solid solvent
Easy · Level 3View options
Vapour pressure decreases, so a higher temperature is needed for boiling
Vapour pressure increases, so the boiling point decreases
Vapour pressure does not change, but the boiling point increases
The two effects have no relation
Easy · Level 3View options
The mole fraction of solute particles
The colour of the solvent
The shape of the container
The smell of the solution
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The solute produces more particles in the solution
The solute has a darker colour
The solvent volume remains constant
The solute is less soluble
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They have the same osmotic pressure
They have the same colour
Their boiling points are always identical
They must contain the same solute
Easy · Level 3View options
Osmosis
Diffusion
Evaporation
Boiling
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The nature of the solvent
The nature of the solute
The colour of the solute
The container of the solution
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Freezing-point depression for a one-molal solution
Boiling point of a one-molar solution
Mass of the solute
Vapour pressure of the solvent
Easy · Level 3View options
300 K
27 K
273 K
246 K
Easy · Level 3View options
The vapour pressure of solution decreases
Solute evaporates quickly
Mass of solvent becomes zero
Temperature does not increase in solution
Easy · Level 3View options
Solute particles hinder crystal formation of solvent
The solute itself freezes first
The temperature of the solvent increases
The colour of the solution changes
Easy · Level 3View options
3
2
1
4
Easy · Level 3View options
2
1/2
1
0
Easy · Level 3View options
From concentrated solution to dilute solution
From dilute solution to concentrated solution
Equally in both directions
The solvent does not move
Easy · Level 3View options
Osmotic pressure
Vapour pressure
Atmospheric temperature
Freezing point
Easy · Level 3View options
2
1
0.5
3
Easy · Level 3View options
Chemical nature of the particles
Number of solute particles
Amount of solute particles
van’t Hoff factor
Easy · Level 3View options
Depression of freezing point and osmotic pressure
Viscosity and surface tension
Colour and odour
Density and refractive index
Easy · Level 3View options
Because of dissolved salt particles
Because of the depth of the sea
Because of the blue colour of water
Only because of air pressure
Question 1EasyLevel 3
What happens if a blood cell is placed in a highly concentrated salt solution?
Correct answer: B
A highly concentrated salt solution is hypertonic relative to the fluid inside a blood cell. Across the selectively permeable cell membrane, water moves by osmosis from the region of lower solute concentration inside the cell toward the region of higher solute concentration outside. As water leaves, the cell loses volume and shrinks. This process is called crenation in red blood cells.
What is the main reason for the elevation of the boiling point of a solution?
Correct answer: A
A liquid boils when its vapour pressure becomes equal to the external pressure. When a non-volatile solute is dissolved in a solvent, the mole fraction and escaping tendency of the solvent decrease, so the solution has a lower vapour pressure than the pure solvent at the same temperature. The solution must therefore be heated to a higher temperature to reach external pressure. Thus its boiling point rises, making option A correct.
Which solution will have the highest osmotic pressure at the same temperature if all solutions are 0.1 M and dissociation is complete?
Correct answer: C
For a dilute solution, osmotic pressure is π = iCRT. Because concentration C and temperature T are the same for every option, osmotic pressure depends on the van’t Hoff factor i. Urea and glucose are non-electrolytes, so i = 1; NaCl gives two ions, so i = 2; MgCl₂ gives Mg²⁺ and two Cl⁻ ions, so i = 3 under complete dissociation. Therefore MgCl₂ has the highest osmotic pressure, option C.
A solution has a freezing-point depression of 0.93 K. If Kf = 1.86 K kg mol⁻¹ and the solute is non-dissociated, what is the molality?
Correct answer: B
The freezing-point depression equation is ΔTf = iKf m. Since the solute is non-dissociated, i = 1. Rearranging gives m = ΔTf/(iKf) = 0.93/(1 × 1.86) mol kg⁻¹ = 0.50 mol kg⁻¹. Molality is normally written as 0.50 m. The negative sign in the actual freezing temperature change only indicates lowering; the given depression is already its positive magnitude. Thus option B is correct.
For an associated solute, the van’t Hoff factor is i = 0.75. How will the colligative effect compare with that of a normal non-dissociated solute at the same concentration?
Correct answer: B
For a given solvent, concentration, and temperature, each colligative effect is proportional to the van’t Hoff factor i. A normal non-dissociated solute has i = 1, whereas the associated solute has i = 0.75 because some solute particles combine and the total number of particles decreases. Therefore its colligative effect is 0.75 times, or 75% of, the normal effect. Hence option B is correct.
Which of the following properties depends on the number of solute particles present in a solution rather than on their chemical nature?
Correct answer: C
A colligative property depends primarily on the number of dissolved particles, not on the chemical identity of those particles. Osmotic pressure is one of the four principal colligative properties and is represented for a dilute solution by π = CRT, where C indicates the concentration of solute particles. Viscosity, surface tension, and refractive index also depend strongly on molecular nature.
Why is osmotic pressure considered a colligative property?
Correct answer: B
A colligative property is controlled by the number of dissolved particles in a specified amount of solvent, rather than by the chemical identity of the solute. Osmotic pressure follows π = CRT for a dilute solution, so it depends on particle concentration. If a solute dissociates, the increased number of particles increases osmotic pressure; if particles associate, the effect decreases.
What is the correct relation between lowering of vapour pressure and elevation of boiling point when a non-volatile solute is added?
Correct answer: A
Adding a non-volatile solute lowers the vapour pressure of the solution at every given temperature because fewer solvent molecules can escape into the vapour phase. Boiling occurs when vapour pressure equals external pressure. Therefore, the solution must be heated to a higher temperature to reach that pressure, producing elevation of the boiling point. Thus the two effects are directly connected.
When a non-volatile solute is added to a solution, relative lowering of vapour pressure mainly depends on what?
Correct answer: A
For a solution containing a non-volatile solute, Raoult's law gives the relative lowering of vapour pressure as (p° − p)/p° = x_solute, for an ideal dilute solution. Therefore, the effect depends on the mole fraction, or effective number, of solute particles. It does not depend on colour, smell, or container shape. If the solute dissociates or associates, the effective particle number must be considered.
If a solute causes a larger depression in freezing point, what is the most suitable reason?
Correct answer: A
Freezing-point depression is a colligative property and is determined by the number of dissolved particles. The relation ΔT_f = iK_fm shows that, at a fixed solvent and molality, a larger van't Hoff factor i produces a larger depression. Ionic compounds can dissociate into several ions, increasing the effective particle count. Colour, constant volume, or low solubility does not by itself explain a larger depression.
Which statement about isotonic solutions is correct?
Correct answer: A
Two solutions are isotonic when, at the same temperature, they exert equal osmotic pressure across a semipermeable membrane. Their solutes need not be chemically identical; different solutes can produce the same effective concentration of particles. Equal osmotic pressure does not mean that colour, composition, or every other physical property is identical. Thus, option A gives the defining property of isotonic solutions.
Movement of solvent molecules through a semipermeable membrane from a dilute solution to a concentrated solution is an example of which process?
Correct answer: A
Osmosis is the net movement of solvent molecules through a semipermeable membrane from the side with lower solute concentration or higher solvent potential to the side with higher solute concentration or lower solvent potential. The membrane permits solvent molecules to pass while restricting solute particles. Diffusion does not specifically require a semipermeable membrane, whereas evaporation and boiling are phase changes rather than this membrane-mediated transport.
The constant Kb used in boiling-point elevation depends on what?
Correct answer: A
Kb is the molal elevation constant, also called the ebullioscopic constant. It appears in the relation ΔTb = iKb m. Its value is a characteristic property of the solvent because it depends on solvent properties such as its boiling point, enthalpy of vaporisation, and molar mass. For a specified solvent, Kb does not depend on the chemical identity or colour of the dissolved solute. The solute affects the factor i and molality m instead.
What is the correct meaning of the constant Kf used in freezing-point depression?
Correct answer: A
Kf is the molal depression constant, also called the cryoscopic constant. It is defined as the decrease in the freezing point produced when one mole of a non-volatile, non-electrolyte solute is dissolved in one kilogram of solvent, under ideal dilute-solution conditions. The equation is ΔTf = iKf m. Its value depends on the solvent, and molality—not molarity—is used because molality is independent of temperature-related volume changes.
If the osmotic pressure of a solution is measured at 27 °C, what temperature value should be used in the formula?
Correct answer: A
Temperature in the osmotic-pressure equation π = iCRT must be expressed on the absolute Kelvin scale. To convert Celsius to Kelvin, add 273.15, or approximately 273 for school-level calculations. Thus, 27 °C = 27 + 273 = 300 K, approximately 300.15 K if greater precision is required. Using 27 directly would be incorrect because gas-law and osmotic-pressure relations require absolute temperature.
Why is the boiling point of a solution higher than that of the pure solvent?
Correct answer: A
A non-volatile solute lowers the vapour pressure of the solvent in the solution. Boiling occurs when vapour pressure becomes equal to external pressure. Because the solution has a lower vapour pressure at the same temperature, it must be heated to a higher temperature to boil. This increase is called elevation of boiling point, a colligative property.
Why is the freezing point of a solution lower than that of the pure solvent?
Correct answer: A
Freezing requires solvent molecules to arrange themselves into an ordered solid crystal. Dissolved solute particles disturb this arrangement and reduce the escaping tendency of solvent molecules into the solid phase. Therefore, the solution must be cooled to a lower temperature before equilibrium between liquid and solid is reached. This is called depression of freezing point.
If an electrolyte of type AB₂ dissociates completely, what will be its ideal van't Hoff factor?
Correct answer: A
Complete dissociation of one formula unit of AB₂ produces one A ion and two B ions: AB₂ → A + 2B. Thus, one original particle becomes three particles in solution. The ideal van't Hoff factor is the ratio of the total particles after dissociation to the original number of formula units, so i = 3/1 = 3, assuming no association or other non-ideal effects.
In a solution, the actual number of solute particles is twice the expected number. What is its van't Hoff factor?
Correct answer: A
The van't Hoff factor measures the change in the number of dissolved particles: i = actual number of particles divided by the number expected if no dissociation or association occurred. Since the actual number is twice the expected number, i = 2N/N = 2. A value greater than one generally indicates particle formation through dissociation, although the numerical definition itself is based on the particle ratio.
In reverse osmosis, in which direction does the solvent move?
Correct answer: A
In ordinary osmosis, solvent passes through a semipermeable membrane from the dilute side, which has lower solute concentration, toward the concentrated side. In reverse osmosis, an external pressure greater than the osmotic pressure is applied on the concentrated solution. This forces solvent to move in the opposite direction, from the concentrated solution toward the dilute or purified side.
For reverse osmosis, the applied external pressure must be greater than what?
Correct answer: A
Osmotic pressure is the minimum pressure that must be applied to the solution side to stop the natural flow of solvent through a semipermeable membrane. To make the solvent flow in the reverse direction, the applied pressure must exceed this osmotic pressure. Vapour pressure, temperature, and freezing point do not provide the relevant pressure comparison for reverse osmosis.
If 2 moles of particles are effectively present in a solution while 1 mole was expected for the ideal non-dissociated state, what is the van't Hoff factor i?
Correct answer: A
The van't Hoff factor is defined as i = effective number of solute particles actually present divided by the number expected for the undissociated solute. In this case, the effective particle amount is 2 mol and the expected amount is 1 mol. Therefore, i = 2/1 = 2. The value above one indicates that the number of particles has increased, as in dissociation.
Which property of a solute is not important for determining colligative properties?
Correct answer: A
Colligative properties depend primarily on the number of independently moving solute particles present in a solution, not on the chemical identity of those particles. The number of moles and the van’t Hoff factor help determine the effective particle concentration. Thus, under the ideal dilute-solution assumption, chemical nature is not the determining factor.
The four standard colligative properties are relative lowering of vapour pressure, elevation of boiling point, depression of freezing point, and osmotic pressure. Freezing-point depression and osmotic pressure therefore form a pair consisting entirely of colligative properties. Viscosity, colour, density, and refractive index depend on factors other than only the number of solute particles.
Why is the freezing point of seawater lower than that of pure water?
Correct answer: A
Seawater contains dissolved sodium chloride and other salts. These solutes increase the number of particles in the liquid phase and lower its freezing point, according to the colligative property called depression of freezing point. Therefore seawater must be cooled below the freezing point of pure water before it solidifies. The colour and depth are not the primary explanation.
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