सूत्र \(^{n}C_r=\frac{^{n}P_r}{r!}\) में (r!) से भाग क्यों दिया जाता है?

Why do we divide by (r!) in \(^{n}C_r=\frac{^{n}P_r}{r!}\)?

Explanation opens after your attempt
Correct Answer

D. क्योंकि क्रम को हटाना होता हैBecause order has to be removed

Step 1

Concept

In combination order is not counted so (r!) orders of selected objects are removed. In exams treat combination as selection without order.

Step 2

Why this answer is correct

The correct answer is D. क्योंकि क्रम को हटाना होता है / Because order has to be removed. In combination order is not counted so (r!) orders of selected objects are removed. In exams treat combination as selection without order.

Step 3

Exam Tip

Combination में क्रम नहीं गिना जाता इसलिए चुनी गई (r) वस्तुओं के (r!) क्रम हटते हैं। परीक्षा में combination को बिना क्रम का चयन मानें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

सूत्र \(^{n}C_r=\frac{^{n}P_r}{r!}\) में (r!) से भाग क्यों दिया जाता है? / Why do we divide by (r!) in \(^{n}C_r=\frac{^{n}P_r}{r!}\)?

Correct Answer: D. क्योंकि क्रम को हटाना होता है / Because order has to be removed. Explanation: Combination में क्रम नहीं गिना जाता इसलिए चुनी गई (r) वस्तुओं के (r!) क्रम हटते हैं। परीक्षा में combination को बिना क्रम का चयन मानें। / In combination order is not counted so (r!) orders of selected objects are removed. In exams treat combination as selection without order.

Which concept should I revise for this Mathematics MCQ?

In combination order is not counted so (r!) orders of selected objects are removed. In exams treat combination as selection without order.

What exam hint can help solve this Mathematics question?

Combination में क्रम नहीं गिना जाता इसलिए चुनी गई (r) वस्तुओं के (r!) क्रम हटते हैं। परीक्षा में combination को बिना क्रम का चयन मानें।