ग्राफ \(y=\sqrt{|x|}\) किस सममिति को दिखाता है?

Which symmetry is shown by the graph \(y=\sqrt{|x|}\)?

Explanation opens after your attempt
Correct Answer

B. (y)-अक्ष के प्रतिabout the (y)-axis

Step 1

Concept

Since \(\sqrt{|{-x}|}=\sqrt{|x|}\), the function is even. In exams, identify (y)-axis symmetry from (f(-x)=f(x)).

Step 2

Why this answer is correct

The correct answer is B. (y)-अक्ष के प्रति / about the (y)-axis. Since \(\sqrt{|{-x}|}=\sqrt{|x|}\), the function is even. In exams, identify (y)-axis symmetry from (f(-x)=f(x)).

Step 3

Exam Tip

\(\sqrt{|{-x}|}=\sqrt{|x|}\) इसलिए फलन सम है। परीक्षा में (f(-x)=f(x)) से (y)-अक्ष सममिति पहचानें।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=\sqrt{|x|}\) किस सममिति को दिखाता है? / Which symmetry is shown by the graph \(y=\sqrt{|x|}\)?

Correct Answer: B. (y)-अक्ष के प्रति / about the (y)-axis. Explanation: \(\sqrt{|{-x}|}=\sqrt{|x|}\) इसलिए फलन सम है। परीक्षा में (f(-x)=f(x)) से (y)-अक्ष सममिति पहचानें। / Since \(\sqrt{|{-x}|}=\sqrt{|x|}\), the function is even. In exams, identify (y)-axis symmetry from (f(-x)=f(x)).

Which concept should I revise for this Mathematics MCQ?

Since \(\sqrt{|{-x}|}=\sqrt{|x|}\), the function is even. In exams, identify (y)-axis symmetry from (f(-x)=f(x)).

What exam hint can help solve this Mathematics question?

\(\sqrt{|{-x}|}=\sqrt{|x|}\) इसलिए फलन सम है। परीक्षा में (f(-x)=f(x)) से (y)-अक्ष सममिति पहचानें।