कौन-सा कथन ग्राफ \(y=-\sqrt{x+1}\) के लिए सही है?
Which statement is correct for the graph \(y=-\sqrt{x+1}\)?
Explanation opens after your attempt
A. प्रांत \([-1,\infty\)) और परिसर (\(-\infty,0]\)domain \([-1,\infty\)) and range (\(-\infty,0]\)
Concept
From \(x+1\ge0\), the domain is \([-1,\infty\)), and the negative sign gives \(y\le0\). In exams, check both the square root and the outside negative sign.
Why this answer is correct
The correct answer is A. प्रांत \([-1,\infty\)) और परिसर (\(-\infty,0]\) / domain \([-1,\infty\)) and range (\(-\infty,0]\). From \(x+1\ge0\), the domain is \([-1,\infty\)), and the negative sign gives \(y\le0\). In exams, check both the square root and the outside negative sign.
Exam Tip
\(x+1\ge0\) से प्रांत \([-1,\infty\)) है और ऋण चिह्न से \(y\le0\)। परीक्षा में वर्गमूल और बाहरी ऋण दोनों का प्रभाव देखें।
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