असमानता \(2x+5\ge 17\) का अंतराल रूप कौन सा है?

Which interval form represents the solution of \(2x+5\ge 17\)?

Explanation opens after your attempt
Correct Answer

A. \([6,\infty\))

Step 1

Concept

The solution is \(x\ge 6\), so the interval is \([6,\infty\)). The sign \(\ge\) uses a closed bracket.

Step 2

Why this answer is correct

The correct answer is A. \([6,\infty\)). The solution is \(x\ge 6\), so the interval is \([6,\infty\)). The sign \(\ge\) uses a closed bracket.

Step 3

Exam Tip

हल \(x\ge 6\) है, इसलिए अंतराल \([6,\infty\)) होगा। \(\ge\) में बंद कोष्ठक लगता है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(2x+5\ge 17\) का अंतराल रूप कौन सा है? / Which interval form represents the solution of \(2x+5\ge 17\)?

Correct Answer: A. \([6,\infty\)). Explanation: हल \(x\ge 6\) है, इसलिए अंतराल \([6,\infty\)) होगा। \(\ge\) में बंद कोष्ठक लगता है। / The solution is \(x\ge 6\), so the interval is \([6,\infty\)). The sign \(\ge\) uses a closed bracket.

Which concept should I revise for this Mathematics MCQ?

The solution is \(x\ge 6\), so the interval is \([6,\infty\)). The sign \(\ge\) uses a closed bracket.

What exam hint can help solve this Mathematics question?

हल \(x\ge 6\) है, इसलिए अंतराल \([6,\infty\)) होगा। \(\ge\) में बंद कोष्ठक लगता है।