कौन-सी expression \(^{n}C_2\) को \(^{n}P_2\) से सही जोड़ती है?
Which expression correctly connects \(^{n}C_2\) with \(^{n}P_2\)?
Explanation opens after your attempt
Correct Answer
B. \(^{n}C_2=\frac{^{n}P_2}{2!}\)
Concept
To get unordered pairs from ordered pairs (2!) orders are removed. This connection is very useful in pair selection exams.
Why this answer is correct
The correct answer is B. \(^{n}C_2=\frac{^{n}P_2}{2!}\). To get unordered pairs from ordered pairs (2!) orders are removed. This connection is very useful in pair selection exams.
Exam Tip
Ordered pair से unordered pair पाने के लिए (2!) orders हटते हैं। परीक्षा में pair selection में यह connection बहुत उपयोगी है।
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