योग \( \sum_{r=0}^{4}\binom{6}{r}\binom{8}{4-r} \) का मान क्या है?

What is the value of \( \sum_{r=0}^{4}\binom{6}{r}\binom{8}{4-r} \)?

Explanation opens after your attempt
Correct Answer

C. (1001)

Step 1

Concept

By Vandermonde's identity, the sum is \( \binom{14}{4}=1001 \). In such sums, view it as total selection after adding upper counts.

Step 2

Why this answer is correct

The correct answer is C. (1001). By Vandermonde's identity, the sum is \( \binom{14}{4}=1001 \). In such sums, view it as total selection after adding upper counts.

Step 3

Exam Tip

वैंडरमोंड सर्वसमिका से योग \( \binom{14}{4}=1001 \) है। ऐसे योग में ऊपर की संख्याएँ जोड़कर कुल चयन देखें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

योग \( \sum_{r=0}^{4}\binom{6}{r}\binom{8}{4-r} \) का मान क्या है? / What is the value of \( \sum_{r=0}^{4}\binom{6}{r}\binom{8}{4-r} \)?

Correct Answer: C. (1001). Explanation: वैंडरमोंड सर्वसमिका से योग \( \binom{14}{4}=1001 \) है। ऐसे योग में ऊपर की संख्याएँ जोड़कर कुल चयन देखें। / By Vandermonde's identity, the sum is \( \binom{14}{4}=1001 \). In such sums, view it as total selection after adding upper counts.

Which concept should I revise for this Mathematics MCQ?

By Vandermonde's identity, the sum is \( \binom{14}{4}=1001 \). In such sums, view it as total selection after adding upper counts.

What exam hint can help solve this Mathematics question?

वैंडरमोंड सर्वसमिका से योग \( \binom{14}{4}=1001 \) है। ऐसे योग में ऊपर की संख्याएँ जोड़कर कुल चयन देखें।