Class 11 Mathematics Permutations and Combinations Factorial notation Medium Level 57

(\frac{(n+3)!-(n+2)!}{(n+2)!}) का सरल रूप क्या है?

What is the simplified form of (\frac{(n+3)!-(n+2)!}{(n+2)!})?

Explanation opens after your attempt
Correct Answer

B. (n+2)

Step 1

Concept

((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!). Therefore the value is (n+2).

Step 2

Why this answer is correct

The correct answer is B. (n+2). ((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!). Therefore the value is (n+2).

Step 3

Exam Tip

((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!)। इसलिए मान (n+2) है।

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(\frac{(n+3)!-(n+2)!}{(n+2)!}) का सरल रूप क्या है? / What is the simplified form of (\frac{(n+3)!-(n+2)!}{(n+2)!})?

Correct Answer: B. (n+2). Explanation: ((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!)। इसलिए मान (n+2) है। / ((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!). Therefore the value is (n+2).

Which concept should I revise for this Mathematics MCQ?

((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!). Therefore the value is (n+2).

What exam hint can help solve this Mathematics question?

((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!)। इसलिए मान (n+2) है।