फलन (f(x)=\sqrt{4-x-2}) की रेंज क्या है?
What is the range of (f(x)=\sqrt{4-x-2})?
Explanation opens after your attempt
A. ([0,2])
Concept
On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.
Why this answer is correct
The correct answer is A. ([0,2]). On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.
Exam Tip
डोमेन पर \(0\le 4-x^2\le 4\), इसलिए (0\le f(x)\le 2)। परीक्षा में वर्गमूल की रेंज हमेशा non-negative होती है।
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