फलन (f(x)=\sqrt{4-x-2}) की रेंज क्या है?

What is the range of (f(x)=\sqrt{4-x-2})?

Explanation opens after your attempt
Correct Answer

A. ([0,2])

Step 1

Concept

On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.

Step 2

Why this answer is correct

The correct answer is A. ([0,2]). On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.

Step 3

Exam Tip

डोमेन पर \(0\le 4-x^2\le 4\), इसलिए (0\le f(x)\le 2)। परीक्षा में वर्गमूल की रेंज हमेशा non-negative होती है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{4-x-2}) की रेंज क्या है? / What is the range of (f(x)=\sqrt{4-x-2})?

Correct Answer: A. ([0,2]). Explanation: डोमेन पर \(0\le 4-x^2\le 4\), इसलिए (0\le f(x)\le 2)। परीक्षा में वर्गमूल की रेंज हमेशा non-negative होती है। / On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.

Which concept should I revise for this Mathematics MCQ?

On the domain, \(0\le 4-x^2\le 4\), so (0\le f(x)\le 2). In exams the range of a square root is always non-negative.

What exam hint can help solve this Mathematics question?

डोमेन पर \(0\le 4-x^2\le 4\), इसलिए (0\le f(x)\le 2)। परीक्षा में वर्गमूल की रेंज हमेशा non-negative होती है।