फलन (f(x)=\frac{x}{\sqrt{x-2+1}}) का परिसर क्या है?

What is the range of (f(x)=\frac{x}{\sqrt{x-2+1}})?

Explanation opens after your attempt
Correct Answer

A. ((-1,1))

Step 1

Concept

The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.

Step 2

Why this answer is correct

The correct answer is A. ((-1,1)). The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.

Step 3

Exam Tip

हर हमेशा (|x|) से बड़ा होता है, इसलिए (-1<f(x)<1)। (-1) और (1) केवल सीमा मान हैं।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{x}{\sqrt{x-2+1}}) का परिसर क्या है? / What is the range of (f(x)=\frac{x}{\sqrt{x-2+1}})?

Correct Answer: A. ((-1,1)). Explanation: हर हमेशा (|x|) से बड़ा होता है, इसलिए (-1<f(x)<1)। (-1) और (1) केवल सीमा मान हैं। / The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.

Which concept should I revise for this Mathematics MCQ?

The denominator is always greater than (|x|), so (-1<f(x)<1). The values (-1) and (1) are only limiting values.

What exam hint can help solve this Mathematics question?

हर हमेशा (|x|) से बड़ा होता है, इसलिए (-1<f(x)<1)। (-1) और (1) केवल सीमा मान हैं।