फलन (f(x)=\frac{x-2}{x-2+1}) की रेंज क्या है?
What is the range of (f(x)=\frac{x-2}{x-2+1})?
Explanation opens after your attempt
Correct Answer
A. ([0,1))
Concept
Since \(x^2\ge 0\), the output can be (0), but it never reaches (1). In exams \(\frac{x^2}{x^2+1}=1-\frac{1}{x^2+1}\) is useful.
Why this answer is correct
The correct answer is A. ([0,1)). Since \(x^2\ge 0\), the output can be (0), but it never reaches (1). In exams \(\frac{x^2}{x^2+1}=1-\frac{1}{x^2+1}\) is useful.
Exam Tip
\(x^2\ge 0\) से आउटपुट (0) मिल सकता है, पर (1) कभी नहीं मिलता। परीक्षा में \(\frac{x^2}{x^2+1}=1-\frac{1}{x^2+1}\) उपयोगी है।
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