फलन (f(x)=\frac{x-2+5}{x-2+1}) की रेंज क्या है?

What is the range of (f(x)=\frac{x-2+5}{x-2+1})?

Explanation opens after your attempt
Correct Answer

A. ((1,5])

Step 1

Concept

\(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\). The maximum (5) is attained, but (1) is only a limit.

Step 2

Why this answer is correct

The correct answer is A. ((1,5]). \(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\). The maximum (5) is attained, but (1) is only a limit.

Step 3

Exam Tip

\(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\) है। अधिकतम (5) मिलता है, लेकिन (1) केवल limit है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{x-2+5}{x-2+1}) की रेंज क्या है? / What is the range of (f(x)=\frac{x-2+5}{x-2+1})?

Correct Answer: A. ((1,5]). Explanation: \(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\) है। अधिकतम (5) मिलता है, लेकिन (1) केवल limit है। / \(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\). The maximum (5) is attained, but (1) is only a limit.

Which concept should I revise for this Mathematics MCQ?

\(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\). The maximum (5) is attained, but (1) is only a limit.

What exam hint can help solve this Mathematics question?

\(\frac{x^2+5}{x^2+1}=1+\frac{4}{x^2+1}\) है। अधिकतम (5) मिलता है, लेकिन (1) केवल limit है।