फलन (f(x)=2\sqrt{x+1}-5) का परिसर क्या है?
What is the range of (f(x)=2\sqrt{x+1}-5)?
Explanation opens after your attempt
Correct Answer
A. \([-5,\infty\))
Concept
Since \(\sqrt{x+1}\ge 0\), \(2\sqrt{x+1}-5\ge -5\). Hence the range is \([-5,\infty\)).
Why this answer is correct
The correct answer is A. \([-5,\infty\)). Since \(\sqrt{x+1}\ge 0\), \(2\sqrt{x+1}-5\ge -5\). Hence the range is \([-5,\infty\)).
Exam Tip
\(\sqrt{x+1}\ge 0\), इसलिए \(2\sqrt{x+1}-5\ge -5\)। अतः परिसर \([-5,\infty\)) है।
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