\(^{n}C_2=\frac{^{n}P_2}{2!}\) में (2!) से भाग का pair-counting अर्थ क्या है?

What is the pair-counting meaning of dividing by (2!) in \(^{n}C_2=\frac{^{n}P_2}{2!}\)?

Explanation opens after your attempt
Correct Answer

B. हर unordered pair दो orders में गिना गया हैEach unordered pair is counted in two orders

Step 1

Concept

(AB) and (BA) are the same unordered pair. In exams divide by (2!) when there is no direction.

Step 2

Why this answer is correct

The correct answer is B. हर unordered pair दो orders में गिना गया है / Each unordered pair is counted in two orders. (AB) and (BA) are the same unordered pair. In exams divide by (2!) when there is no direction.

Step 3

Exam Tip

(AB) और (BA) एक ही unordered pair हैं। परीक्षा में direction न हो तो (2!) से divide करें।

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Mathematics Answer, Explanation and Revision Hints

\(^{n}C_2=\frac{^{n}P_2}{2!}\) में (2!) से भाग का pair-counting अर्थ क्या है? / What is the pair-counting meaning of dividing by (2!) in \(^{n}C_2=\frac{^{n}P_2}{2!}\)?

Correct Answer: B. हर unordered pair दो orders में गिना गया है / Each unordered pair is counted in two orders. Explanation: (AB) और (BA) एक ही unordered pair हैं। परीक्षा में direction न हो तो (2!) से divide करें। / (AB) and (BA) are the same unordered pair. In exams divide by (2!) when there is no direction.

Which concept should I revise for this Mathematics MCQ?

(AB) and (BA) are the same unordered pair. In exams divide by (2!) when there is no direction.

What exam hint can help solve this Mathematics question?

(AB) और (BA) एक ही unordered pair हैं। परीक्षा में direction न हो तो (2!) से divide करें।