व्यवस्था \(x\le6\), \(y\le5\), \(x+y\ge4\), \(x\ge0\), \(y\ge0\) का हल क्षेत्र कैसा है?
What is the nature of the solution region for \(x\le6\), \(y\le5\), \(x+y\ge4\), \(x\ge0\), \(y\ge0\)?
Explanation opens after your attempt
Correct Answer
B. सीमितBounded
Concept
The conditions \(0\le x\le6\) and \(0\le y\le5\) restrict the region inside a rectangle. The inequality \(x+y\ge4\) only cuts off one corner.
Why this answer is correct
The correct answer is B. सीमित / Bounded. The conditions \(0\le x\le6\) and \(0\le y\le5\) restrict the region inside a rectangle. The inequality \(x+y\ge4\) only cuts off one corner.
Exam Tip
\(0\le x\le6\) और \(0\le y\le5\) क्षेत्र को आयत में सीमित करते हैं। \(x+y\ge4\) केवल उसका एक कोना काटता है।
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