ग्राफ \(y=3-\sqrt{x-1}\) का अधिकतम मान क्या है?

What is the maximum value of the graph \(y=3-\sqrt{x-1}\)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

Since \(\sqrt{x-1}\ge0\) and its least value is (0) at (x=1), \(y\le3\). In exams, for a negative square-root graph, check the starting point for maximum.

Step 2

Why this answer is correct

The correct answer is C. (3). Since \(\sqrt{x-1}\ge0\) and its least value is (0) at (x=1), \(y\le3\). In exams, for a negative square-root graph, check the starting point for maximum.

Step 3

Exam Tip

\(\sqrt{x-1}\ge0\) और सबसे छोटा मान (0) (x=1) पर है इसलिए \(y\le3\)। परीक्षा में ऋणात्मक वर्गमूल वाले ग्राफ का अधिकतम आरंभिक बिंदु पर देखें।

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ग्राफ \(y=3-\sqrt{x-1}\) का अधिकतम मान क्या है? / What is the maximum value of the graph \(y=3-\sqrt{x-1}\)?

Correct Answer: C. (3). Explanation: \(\sqrt{x-1}\ge0\) और सबसे छोटा मान (0) (x=1) पर है इसलिए \(y\le3\)। परीक्षा में ऋणात्मक वर्गमूल वाले ग्राफ का अधिकतम आरंभिक बिंदु पर देखें। / Since \(\sqrt{x-1}\ge0\) and its least value is (0) at (x=1), \(y\le3\). In exams, for a negative square-root graph, check the starting point for maximum.

Which concept should I revise for this Mathematics MCQ?

Since \(\sqrt{x-1}\ge0\) and its least value is (0) at (x=1), \(y\le3\). In exams, for a negative square-root graph, check the starting point for maximum.

What exam hint can help solve this Mathematics question?

\(\sqrt{x-1}\ge0\) और सबसे छोटा मान (0) (x=1) पर है इसलिए \(y\le3\)। परीक्षा में ऋणात्मक वर्गमूल वाले ग्राफ का अधिकतम आरंभिक बिंदु पर देखें।