फलन (f(x)=\sqrt{x+2}+\sqrt{6-x}) का अधिकतम मान क्या है?

What is the maximum value of (f(x)=\sqrt{x+2}+\sqrt{6-x})?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).

Step 2

Why this answer is correct

The correct answer is A. (4). On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).

Step 3

Exam Tip

प्रांत ([-2,6]) पर योग सममित है और अधिकतम (x=2) पर मिलता है। तब मान \(\sqrt{4}+\sqrt{4}=4\) है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{x+2}+\sqrt{6-x}) का अधिकतम मान क्या है? / What is the maximum value of (f(x)=\sqrt{x+2}+\sqrt{6-x})?

Correct Answer: A. (4). Explanation: प्रांत ([-2,6]) पर योग सममित है और अधिकतम (x=2) पर मिलता है। तब मान \(\sqrt{4}+\sqrt{4}=4\) है। / On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).

Which concept should I revise for this Mathematics MCQ?

On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).

What exam hint can help solve this Mathematics question?

प्रांत ([-2,6]) पर योग सममित है और अधिकतम (x=2) पर मिलता है। तब मान \(\sqrt{4}+\sqrt{4}=4\) है।