सबसे छोटा धनात्मक पूर्णांक (n) क्या है ताकि \(\frac{5\pi}{12}+\frac{n\pi}{6}\) और \(\frac{17\pi}{12}\) सहप्रारंभी हों?

What is the least positive integer (n) such that \(\frac{5\pi}{12}+\frac{n\pi}{6}\) and \(\frac{17\pi}{12}\) are coterminal?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

Equating them gives \(\frac{n\pi}{6}=\pi\). Hence (n=6).

Step 2

Why this answer is correct

The correct answer is C. (6). Equating them gives \(\frac{n\pi}{6}=\pi\). Hence (n=6).

Step 3

Exam Tip

दोनों को बराबर करने पर \(\frac{n\pi}{6}=\pi\) मिलता है। इसलिए (n=6) है।

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सबसे छोटा धनात्मक पूर्णांक (n) क्या है ताकि \(\frac{5\pi}{12}+\frac{n\pi}{6}\) और \(\frac{17\pi}{12}\) सहप्रारंभी हों? / What is the least positive integer (n) such that \(\frac{5\pi}{12}+\frac{n\pi}{6}\) and \(\frac{17\pi}{12}\) are coterminal?

Correct Answer: C. (6). Explanation: दोनों को बराबर करने पर \(\frac{n\pi}{6}=\pi\) मिलता है। इसलिए (n=6) है। / Equating them gives \(\frac{n\pi}{6}=\pi\). Hence (n=6).

Which concept should I revise for this Mathematics MCQ?

Equating them gives \(\frac{n\pi}{6}=\pi\). Hence (n=6).

What exam hint can help solve this Mathematics question?

दोनों को बराबर करने पर \(\frac{n\pi}{6}=\pi\) मिलता है। इसलिए (n=6) है।