असमानता \(3-2x\le 9\) का सही हल क्या है?

What is the correct solution of \(3-2x\le 9\)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge -3\)

Step 1

Concept

From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge -3\). From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.

Step 3

Exam Tip

\(3-2x\le 9\) से \(-2x\le 6\) और (-2) से भाग देने पर \(x\ge -3\)। ऋणात्मक भाग दिशा पलटता है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(3-2x\le 9\) का सही हल क्या है? / What is the correct solution of \(3-2x\le 9\)?

Correct Answer: A. \(x\ge -3\). Explanation: \(3-2x\le 9\) से \(-2x\le 6\) और (-2) से भाग देने पर \(x\ge -3\)। ऋणात्मक भाग दिशा पलटता है। / From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.

Which concept should I revise for this Mathematics MCQ?

From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.

What exam hint can help solve this Mathematics question?

\(3-2x\le 9\) से \(-2x\le 6\) और (-2) से भाग देने पर \(x\ge -3\)। ऋणात्मक भाग दिशा पलटता है।