असमानता \(3-2x\le 9\) का सही हल क्या है?
What is the correct solution of \(3-2x\le 9\)?
Explanation opens after your attempt
A. \(x\ge -3\)
Concept
From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.
Why this answer is correct
The correct answer is A. \(x\ge -3\). From \(3-2x\le 9\), we get \(-2x\le 6\), and division by (-2) gives \(x\ge -3\). Negative division reverses the direction.
Exam Tip
\(3-2x\le 9\) से \(-2x\le 6\) और (-2) से भाग देने पर \(x\ge -3\)। ऋणात्मक भाग दिशा पलटता है।
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