फलन (f(x)=\frac{1}{x-2-9}) के ग्राफ के लंबवत आसमापी कौन-से हैं?
What are the vertical asymptotes of the graph of (f(x)=\frac{1}{x-2-9})?
Explanation opens after your attempt
A. (x=-3) और (x=3)(x=-3) and (x=3)
Concept
The denominator (x-2-9=(x-3)(x+3)) is zero at \(x=\pm3\). In exams, find vertical asymptotes from the zeroes of the denominator.
Why this answer is correct
The correct answer is A. (x=-3) और (x=3) / (x=-3) and (x=3). The denominator (x-2-9=(x-3)(x+3)) is zero at \(x=\pm3\). In exams, find vertical asymptotes from the zeroes of the denominator.
Exam Tip
हर (x-2-9=(x-3)(x+3)) शून्य होने पर \(x=\pm3\) मिलता है। परीक्षा में हर के शून्यों से लंबवत आसमापी खोजें।
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