फलन (f(x)=\sqrt{9-x-2}) का ग्राफ किस आकृति का ऊपरी भाग है?
The graph of (f(x)=\sqrt{9-x-2}) is the upper part of which figure?
Explanation opens after your attempt
Correct Answer
A. वृत्त \(x^2+y^2=9\)Circle \(x^2+y^2=9\)
Concept
From \(y=\sqrt{9-x^2}\), we get \(x^2+y^2=9\) with \(y\ge0\). The square root gives only the upper semicircle.
Why this answer is correct
The correct answer is A. वृत्त \(x^2+y^2=9\) / Circle \(x^2+y^2=9\). From \(y=\sqrt{9-x^2}\), we get \(x^2+y^2=9\) with \(y\ge0\). The square root gives only the upper semicircle.
Exam Tip
\(y=\sqrt{9-x^2}\) से \(y^2=9-x^2\), इसलिए \(x^2+y^2=9\) और \(y\ge0\)। वर्गमूल के कारण केवल ऊपरी अर्धवृत्त मिलता है।
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