(n) distinct objects को row में रखना है और (k) special objects का relative order fixed है। Count क्या होगा?
(n) distinct objects are arranged in a row and the relative order of (k) special objects is fixed. What is the count?
Explanation opens after your attempt
A. \(\frac{n!}{k!}\)
Concept
Only (1) of the (k!) relative orders of the special objects is allowed. In exams divide total arrangements by (k!) for fixed relative order.
Why this answer is correct
The correct answer is A. \(\frac{n!}{k!}\). Only (1) of the (k!) relative orders of the special objects is allowed. In exams divide total arrangements by (k!) for fixed relative order.
Exam Tip
Special objects के (k!) relative orders में केवल (1) allowed है। परीक्षा में fixed relative order में total arrangements को (k!) से divide करें।
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