फलन (y=(x+2)3-1) में \(y=x^3\) का बिंदु ((0,0)) किस बिंदु पर जाता है?

In (y=(x+2)3-1), where does the point ((0,0)) of \(y=x^3\) move?

Explanation opens after your attempt
Correct Answer

A. ((-2,-1))

Step 1

Concept

The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).

Step 2

Why this answer is correct

The correct answer is A. ((-2,-1)). The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).

Step 3

Exam Tip

(x+2) ग्राफ को (2) इकाई बाईं ओर और (-1) नीचे ले जाता है। इसलिए ((0,0)) से ((-2,-1)) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

फलन (y=(x+2)3-1) में \(y=x^3\) का बिंदु ((0,0)) किस बिंदु पर जाता है? / In (y=(x+2)3-1), where does the point ((0,0)) of \(y=x^3\) move?

Correct Answer: A. ((-2,-1)). Explanation: (x+2) ग्राफ को (2) इकाई बाईं ओर और (-1) नीचे ले जाता है। इसलिए ((0,0)) से ((-2,-1)) मिलता है। / The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).

Which concept should I revise for this Mathematics MCQ?

The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).

What exam hint can help solve this Mathematics question?

(x+2) ग्राफ को (2) इकाई बाईं ओर और (-1) नीचे ले जाता है। इसलिए ((0,0)) से ((-2,-1)) मिलता है।