व्यवस्था \(x\ge0\), \(y\ge0\), \(x\le4\), \(y\le3\), \(x+y\le8\) में कौन सी असमानता अनावश्यक है?

In \(x\ge0\), \(y\ge0\), \(x\le4\), \(y\le3\), \(x+y\le8\), which inequality is redundant?

Explanation opens after your attempt
Correct Answer

C. \(x+y\le8\)

Step 1

Concept

From \(x\le4\) and \(y\le3\), the maximum possible (x+y) is (7). Hence \(x+y\le8\) does not further reduce the region.

Step 2

Why this answer is correct

The correct answer is C. \(x+y\le8\). From \(x\le4\) and \(y\le3\), the maximum possible (x+y) is (7). Hence \(x+y\le8\) does not further reduce the region.

Step 3

Exam Tip

\(x\le4\) और \(y\le3\) से अधिकतम (x+y=7) हो सकता है। इसलिए \(x+y\le8\) अलग से क्षेत्र नहीं घटाती।

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Mathematics Answer, Explanation and Revision Hints

व्यवस्था \(x\ge0\), \(y\ge0\), \(x\le4\), \(y\le3\), \(x+y\le8\) में कौन सी असमानता अनावश्यक है? / In \(x\ge0\), \(y\ge0\), \(x\le4\), \(y\le3\), \(x+y\le8\), which inequality is redundant?

Correct Answer: C. \(x+y\le8\). Explanation: \(x\le4\) और \(y\le3\) से अधिकतम (x+y=7) हो सकता है। इसलिए \(x+y\le8\) अलग से क्षेत्र नहीं घटाती। / From \(x\le4\) and \(y\le3\), the maximum possible (x+y) is (7). Hence \(x+y\le8\) does not further reduce the region.

Which concept should I revise for this Mathematics MCQ?

From \(x\le4\) and \(y\le3\), the maximum possible (x+y) is (7). Hence \(x+y\le8\) does not further reduce the region.

What exam hint can help solve this Mathematics question?

\(x\le4\) और \(y\le3\) से अधिकतम (x+y=7) हो सकता है। इसलिए \(x+y\le8\) अलग से क्षेत्र नहीं घटाती।