तीन समुच्चयों में (n\(A\cup B\cup C\)=172), केवल (A=38), केवल (B=34), केवल (C=29), केवल \(A\cap B=21\), केवल \(B\cap C=18\) और केवल \(C\cap A=16\) हैं। (n\(A\cap B\cap C\)) कितना होगा?
In three sets (n\(A\cup B\cup C\)=172), only (A=38), only (B=34), only (C=29), only \(A\cap B=21\), only \(B\cap C=18\), and only \(C\cap A=16\). What is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
Correct Answer
A. (16)
Concept
The sum of the six known inside regions is (38+34+29+21+18+16=156), so the central part is (172-156=16). The union contains all seven inside regions.
Why this answer is correct
The correct answer is A. (16). The sum of the six known inside regions is (38+34+29+21+18+16=156), so the central part is (172-156=16). The union contains all seven inside regions.
Exam Tip
ज्ञात छह अंदरूनी क्षेत्रों का योग (38+34+29+21+18+16=156) है, इसलिए केंद्रीय भाग (172-156=16)। संघ में सातों अंदरूनी क्षेत्र आते हैं।
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