तीन समुच्चयों में (n\(A\cup B\cup C\)=150), केवल (A=32), केवल (B=28), केवल (C=24), केवल \(A\cap B=18\), केवल \(B\cap C=16\) और केवल \(C\cap A=14\) हैं। (n\(A\cap B\cap C\)) कितना होगा?
In three sets (n\(A\cup B\cup C\)=150), only (A=32), only (B=28), only (C=24), only \(A\cap B=18\), only \(B\cap C=16\), and only \(C\cap A=14\). What is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
Correct Answer
B. (18)
Concept
The sum of six known inside regions is (32+28+24+18+16+14=132), so the central part is (150-132=18). The union contains all seven inside regions.
Why this answer is correct
The correct answer is B. (18). The sum of six known inside regions is (32+28+24+18+16+14=132), so the central part is (150-132=18). The union contains all seven inside regions.
Exam Tip
ज्ञात छह अंदरूनी क्षेत्रों का योग (32+28+24+18+16+14=132) है, इसलिए केंद्रीय भाग (150-132=18)। संघ में सभी सात अंदरूनी क्षेत्र आते हैं।
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