असमानता \(3x+y\le15\) और \(x+3y\le15\) के पहले चतुर्थांश हल क्षेत्र में रेखाओं का प्रतिच्छेद क्या है?
In the first-quadrant solution region for \(3x+y\le15\) and \(x+3y\le15\), what is the intersection of the two boundary lines?
Explanation opens after your attempt
Correct Answer
A. ( \left\(\frac{15}{4},\frac{15}{4}\right\) )
Concept
Adding the equations gives (4x+4y=30), and by symmetry \(x=y=\frac{15}{4}\). Use symmetry when boundary lines have a similar structure.
Why this answer is correct
The correct answer is A. ( \left\(\frac{15}{4},\frac{15}{4}\right\) ). Adding the equations gives (4x+4y=30), and by symmetry \(x=y=\frac{15}{4}\). Use symmetry when boundary lines have a similar structure.
Exam Tip
दोनों समीकरण जोड़ने पर (4x+4y=30) और सममिति से \(x=y=\frac{15}{4}\) है। समान संरचना वाली रेखाओं में सममिति का उपयोग करें।
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