यदि \(x\in \mathbb{Z}\), \( \frac{2x-7}{3}<5 \) और \( 4-\frac{x}{2}\leq 1 \), तो (x) के कितने पूर्णांक मान संभव हैं?
If \(x\in \mathbb{Z}\), \( \frac{2x-7}{3}<5 \), and \( 4-\frac{x}{2}\leq 1 \), how many integer values of (x) are possible?
Explanation opens after your attempt
Correct Answer
A. (5)
Concept
The first inequality gives (x<11), and the second gives \(x\geq 6\). The integers are (6,7,8,9,10), so there are (5) values.
Why this answer is correct
The correct answer is A. (5). The first inequality gives (x<11), and the second gives \(x\geq 6\). The integers are (6,7,8,9,10), so there are (5) values.
Exam Tip
पहली असमानता से (x<11) और दूसरी से \(x\geq 6\) मिलता है। पूर्णांक (6,7,8,9,10) हैं, इसलिए कुल (5) मान हैं।
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