यदि \(x\in\mathbb{Z}\) और \(-1<2x+3\leq 9\) है तो हल समुच्चय कौन सा है?

If \(x\in\mathbb{Z}\) and \(-1<2x+3\leq 9\), what is the solution set?

Explanation opens after your attempt
Correct Answer

A. ({-1,0,1,2,3})

Step 1

Concept

From \(-1<2x+3\leq 9\), we get \(-4<2x\leq 6\), hence \(-2<x\leq 3\). For integers, handle open and closed endpoints carefully.

Step 2

Why this answer is correct

The correct answer is A. ({-1,0,1,2,3}). From \(-1<2x+3\leq 9\), we get \(-4<2x\leq 6\), hence \(-2<x\leq 3\). For integers, handle open and closed endpoints carefully.

Step 3

Exam Tip

\(-1<2x+3\leq 9\) से \(-4<2x\leq 6\) और \(-2<x\leq 3\) मिलता है। पूर्णांक चुनते समय खुले और बंद सिरों का ध्यान रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in\mathbb{Z}\) और \(-1<2x+3\leq 9\) है तो हल समुच्चय कौन सा है? / If \(x\in\mathbb{Z}\) and \(-1<2x+3\leq 9\), what is the solution set?

Correct Answer: A. ({-1,0,1,2,3}). Explanation: \(-1<2x+3\leq 9\) से \(-4<2x\leq 6\) और \(-2<x\leq 3\) मिलता है। पूर्णांक चुनते समय खुले और बंद सिरों का ध्यान रखें। / From \(-1<2x+3\leq 9\), we get \(-4<2x\leq 6\), hence \(-2<x\leq 3\). For integers, handle open and closed endpoints carefully.

Which concept should I revise for this Mathematics MCQ?

From \(-1<2x+3\leq 9\), we get \(-4<2x\leq 6\), hence \(-2<x\leq 3\). For integers, handle open and closed endpoints carefully.

What exam hint can help solve this Mathematics question?

\(-1<2x+3\leq 9\) से \(-4<2x\leq 6\) और \(-2<x\leq 3\) मिलता है। पूर्णांक चुनते समय खुले और बंद सिरों का ध्यान रखें।