यदि \(U={x:x\in \mathbb{N}, x\leq 20}\) और \(A={x:x\) (20) का धनात्मक भाजक है(}) है, तो (n(A')) कितना होगा?
If \(U={x:x\in \mathbb{N}, x\leq 20}\) and \(A={x:x\) is a positive divisor of (20)(}), what is (n(A'))?
Explanation opens after your attempt
Correct Answer
C. (14)
Concept
The positive divisors of (20) are (1,2,4,5,10,20), so (n(A)=6). Thus (n(A')=20-6=14).
Why this answer is correct
The correct answer is C. (14). The positive divisors of (20) are (1,2,4,5,10,20), so (n(A)=6). Thus (n(A')=20-6=14).
Exam Tip
(20) के धनात्मक भाजक (1,2,4,5,10,20) हैं, इसलिए (n(A)=6)। (n(A')=20-6=14) होगा।
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