यदि \(U={1,2,\ldots,60}\), \(A={x:x\in U,;2\mid x}\) और \(B={x:x\in U,;3\mid x}\) हैं, तो \(|A\cup B|\) कितना है?

If \(U={1,2,\ldots,60}\), \(A={x:x\in U,;2\mid x}\) and \(B={x:x\in U,;3\mid x}\), what is \(|A\cup B|\)?

Explanation opens after your attempt
Correct Answer

A. (40)

Step 1

Concept

Here \(|A\cup B|=30+20-10=40\) because (10) numbers are divisible by (6). In exams, apply inclusion-exclusion first.

Step 2

Why this answer is correct

The correct answer is A. (40). Here \(|A\cup B|=30+20-10=40\) because (10) numbers are divisible by (6). In exams, apply inclusion-exclusion first.

Step 3

Exam Tip

\(|A\cup B|=30+20-10=40\) क्योंकि (6) से विभाज्य (10) संख्याएँ हैं। परीक्षा में समावेशन-अपवर्जन सूत्र पहले लगाएँ।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,60}\), \(A={x:x\in U,;2\mid x}\) और \(B={x:x\in U,;3\mid x}\) हैं, तो \(|A\cup B|\) कितना है? / If \(U={1,2,\ldots,60}\), \(A={x:x\in U,;2\mid x}\) and \(B={x:x\in U,;3\mid x}\), what is \(|A\cup B|\)?

Correct Answer: A. (40). Explanation: \(|A\cup B|=30+20-10=40\) क्योंकि (6) से विभाज्य (10) संख्याएँ हैं। परीक्षा में समावेशन-अपवर्जन सूत्र पहले लगाएँ। / Here \(|A\cup B|=30+20-10=40\) because (10) numbers are divisible by (6). In exams, apply inclusion-exclusion first.

Which concept should I revise for this Mathematics MCQ?

Here \(|A\cup B|=30+20-10=40\) because (10) numbers are divisible by (6). In exams, apply inclusion-exclusion first.

What exam hint can help solve this Mathematics question?

\(|A\cup B|=30+20-10=40\) क्योंकि (6) से विभाज्य (10) संख्याएँ हैं। परीक्षा में समावेशन-अपवर्जन सूत्र पहले लगाएँ।