\(यदि (U={1,2,3,\ldots,40}) और (A={x:x\) 4 या 5 से विभाज्य है\(}) है, तो (n(A^c)) कितना होगा\)?

\(If (U={1,2,3,\ldots,40}) and (A={x:x\) is divisible by 4 or \(5}), what is (n(A^c))\)?

Explanation opens after your attempt
Correct Answer

A. (24)

Step 1

Concept

There are (10) multiples of (4) and (8) multiples of (5), with (2) common multiples of (20). Thus (n(A)=10+8-2=16), so (n\(A^c\)=24).

Step 2

Why this answer is correct

The correct answer is A. (24). There are (10) multiples of (4) and (8) multiples of (5), with (2) common multiples of (20). Thus (n(A)=10+8-2=16), so (n\(A^c\)=24).

Step 3

Exam Tip

(4) के (10) और (5) के (8) गुणज हैं, साझा (20) के (2) गुणज हैं। इसलिए (n(A)=10+8-2=16) और (n\(A^c\)=24)।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,3,\ldots,40}) और (A={x:x\) 4 या 5 से विभाज्य है}) है, तो (n\(A^c\)) कितना होगा? \(/ If (U={1,2,3,\ldots,40}) and (A={x:x\) is divisible by 4 or \(5}), what is (n(A^c))\)?

Correct Answer: A. (24). Explanation: (4) के (10) और (5) के (8) गुणज हैं, साझा (20) के (2) गुणज हैं। इसलिए (n(A)=10+8-2=16) और (n\(A^c\)=24)। / There are (10) multiples of (4) and (8) multiples of (5), with (2) common multiples of (20). Thus (n(A)=10+8-2=16), so (n\(A^c\)=24).

Which concept should I revise for this Mathematics MCQ?

There are (10) multiples of (4) and (8) multiples of (5), with (2) common multiples of (20). Thus (n(A)=10+8-2=16), so (n\(A^c\)=24).

What exam hint can help solve this Mathematics question?

(4) के (10) और (5) के (8) गुणज हैं, साझा (20) के (2) गुणज हैं। इसलिए (n(A)=10+8-2=16) और (n\(A^c\)=24)।