यदि (^{n}C_2=\frac{n(n-1)}{2}) है तो denominator (2) किससे आया?

If (^{n}C_2=\frac{n(n-1)}{2}), where does the denominator (2) come from?

Explanation opens after your attempt
Correct Answer

A. क्योंकि ordered pairs को unordered pairs में बदलने के लिए (2!) से भाग देते हैंBecause ordered pairs are divided by (2!) to become unordered pairs

Step 1

Concept

(AB) and (BA) are the same pair so repetition is removed. In exams (\frac{n(n-1)}{2}) is often useful for pairs.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि ordered pairs को unordered pairs में बदलने के लिए (2!) से भाग देते हैं / Because ordered pairs are divided by (2!) to become unordered pairs. (AB) and (BA) are the same pair so repetition is removed. In exams (\frac{n(n-1)}{2}) is often useful for pairs.

Step 3

Exam Tip

(AB) और (BA) same pair हैं इसलिए दोहराव हटता है। परीक्षा में pairs के लिए अक्सर (\frac{n(n-1)}{2}) उपयोगी है।

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यदि (^{n}C_2=\frac{n(n-1)}{2}) है तो denominator (2) किससे आया? / If (^{n}C_2=\frac{n(n-1)}{2}), where does the denominator (2) come from?

Correct Answer: A. क्योंकि ordered pairs को unordered pairs में बदलने के लिए (2!) से भाग देते हैं / Because ordered pairs are divided by (2!) to become unordered pairs. Explanation: (AB) और (BA) same pair हैं इसलिए दोहराव हटता है। परीक्षा में pairs के लिए अक्सर (\frac{n(n-1)}{2}) उपयोगी है। / (AB) and (BA) are the same pair so repetition is removed. In exams (\frac{n(n-1)}{2}) is often useful for pairs.

Which concept should I revise for this Mathematics MCQ?

(AB) and (BA) are the same pair so repetition is removed. In exams (\frac{n(n-1)}{2}) is often useful for pairs.

What exam hint can help solve this Mathematics question?

(AB) और (BA) same pair हैं इसलिए दोहराव हटता है। परीक्षा में pairs के लिए अक्सर (\frac{n(n-1)}{2}) उपयोगी है।