यदि (n\(A\cup B\cup C\)=180), (n\(A\cap B\cap C\)=20) और ठीक दो समुच्चयों में (70) तत्व हैं, तो ठीक एक समुच्चय में कितने तत्व हैं?

If (n\(A\cup B\cup C\)=180), (n\(A\cap B\cap C\)=20), and (70) elements are in exactly two sets, how many elements are in exactly one set?

Explanation opens after your attempt
Correct Answer

B. (90)

Step 1

Concept

The union equals exactly one plus exactly two plus all three. Therefore exactly one is (180-70-20=90).

Step 2

Why this answer is correct

The correct answer is B. (90). The union equals exactly one plus exactly two plus all three. Therefore exactly one is (180-70-20=90).

Step 3

Exam Tip

संघ (=) ठीक एक (+) ठीक दो (+) तीनों होता है। इसलिए ठीक एक (180-70-20=90)।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\cup B\cup C\)=180), (n\(A\cap B\cap C\)=20) और ठीक दो समुच्चयों में (70) तत्व हैं, तो ठीक एक समुच्चय में कितने तत्व हैं? / If (n\(A\cup B\cup C\)=180), (n\(A\cap B\cap C\)=20), and (70) elements are in exactly two sets, how many elements are in exactly one set?

Correct Answer: B. (90). Explanation: संघ (=) ठीक एक (+) ठीक दो (+) तीनों होता है। इसलिए ठीक एक (180-70-20=90)। / The union equals exactly one plus exactly two plus all three. Therefore exactly one is (180-70-20=90).

Which concept should I revise for this Mathematics MCQ?

The union equals exactly one plus exactly two plus all three. Therefore exactly one is (180-70-20=90).

What exam hint can help solve this Mathematics question?

संघ (=) ठीक एक (+) ठीक दो (+) तीनों होता है। इसलिए ठीक एक (180-70-20=90)।