यदि (n\(A\cup B\)=128), (n\(A\cap B\)=32) और (n(A-B)=45) है, तो (n(B)) कितना होगा?
If (n\(A\cup B\)=128), (n\(A\cap B\)=32), and (n(A-B)=45), what is (n(B))?
Explanation opens after your attempt
C. (83)
Concept
First (n(B-A)=128-45-32=51), then (n(B)=51+32=83). (B) contains only (B) and the common part.
Why this answer is correct
The correct answer is C. (83). First (n(B-A)=128-45-32=51), then (n(B)=51+32=83). (B) contains only (B) and the common part.
Exam Tip
पहले (n(B-A)=128-45-32=51), फिर (n(B)=51+32=83)। (B) में केवल (B) और साझा भाग दोनों आते हैं।
Login to save your score, XP, coins and progress.
