यदि (n(A-B)=x), (n(B-A)=3x), (n\(A\cap B\)=24) और (n\(A\cup B\)=120) है, तो (x) कितना है?
If (n(A-B)=x), (n(B-A)=3x), (n\(A\cap B\)=24), and (n\(A\cup B\)=120), what is (x)?
Explanation opens after your attempt
B. (24)
Concept
From the union regions, (x+3x+24=120), so (4x=96) and (x=24). Solve unknown regions by forming an equation.
Why this answer is correct
The correct answer is B. (24). From the union regions, (x+3x+24=120), so (4x=96) and (x=24). Solve unknown regions by forming an equation.
Exam Tip
संघ के भागों से (x+3x+24=120), इसलिए (4x=96) और (x=24)। अज्ञात क्षेत्र को समीकरण से हल करें।
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