यदि (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), और (n\(A\cap B\cap C\)=1), तो (n\(A\cup B\cup C\)) क्या है?

If (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), and (n\(A\cap B\cap C\)=1), what is (n\(A\cup B\cup C\))?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.

Step 2

Why this answer is correct

The correct answer is A. (16). By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.

Step 3

Exam Tip

तीन समुच्चयों के सूत्र से (8+7+6-2-1-3+1=16)। जोड़ी वाले प्रतिच्छेद घटाकर तीनों का साझा भाग जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), और (n\(A\cap B\cap C\)=1), तो (n\(A\cup B\cup C\)) क्या है? / If (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), and (n\(A\cap B\cap C\)=1), what is (n\(A\cup B\cup C\))?

Correct Answer: A. (16). Explanation: तीन समुच्चयों के सूत्र से (8+7+6-2-1-3+1=16)। जोड़ी वाले प्रतिच्छेद घटाकर तीनों का साझा भाग जोड़ें। / By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.

Which concept should I revise for this Mathematics MCQ?

By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.

What exam hint can help solve this Mathematics question?

तीन समुच्चयों के सूत्र से (8+7+6-2-1-3+1=16)। जोड़ी वाले प्रतिच्छेद घटाकर तीनों का साझा भाग जोड़ें।