यदि (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), और (n\(A\cap B\cap C\)=1), तो (n\(A\cup B\cup C\)) क्या है?
If (n(A)=8), (n(B)=7), (n(C)=6), (n\(A\cap B\)=2), (n\(A\cap C\)=1), (n\(B\cap C\)=3), and (n\(A\cap B\cap C\)=1), what is (n\(A\cup B\cup C\))?
Explanation opens after your attempt
A. (16)
Concept
By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.
Why this answer is correct
The correct answer is A. (16). By the three-set formula, (8+7+6-2-1-3+1=16). Subtract pairwise intersections and add the common part of all three.
Exam Tip
तीन समुच्चयों के सूत्र से (8+7+6-2-1-3+1=16)। जोड़ी वाले प्रतिच्छेद घटाकर तीनों का साझा भाग जोड़ें।
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