यदि (n(A)=73), (n(B)=69) और (n\(A\triangle B\)=88) है, तो (n\(A\cap B\)) कितना है?
If (n(A)=73), (n(B)=69), and (n\(A\triangle B\)=88), what is (n\(A\cap B\))?
Explanation opens after your attempt
Correct Answer
A. (27)
Concept
(n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), so (88=142-2x) gives (x=27). Distinguish exactly one from the common part.
Why this answer is correct
The correct answer is A. (27). (n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), so (88=142-2x) gives (x=27). Distinguish exactly one from the common part.
Exam Tip
(n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), इसलिए (88=142-2x) से (x=27)। ठीक एक और साझा भाग में अंतर करें।
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