यदि (n(A)=16), (n(B)=18), (n(C)=9), (n\(A\cap B\)=6), (n\(A\cap C\)=2), (n\(B\cap C\)=3), और (n\(A\cap B\cap C\)=1), तो (n\(A\cup B\cup C\)) क्या है?
If (n(A)=16), (n(B)=18), (n(C)=9), (n\(A\cap B\)=6), (n\(A\cap C\)=2), (n\(B\cap C\)=3), and (n\(A\cap B\cap C\)=1), what is (n\(A\cup B\cup C\))?
Explanation opens after your attempt
B. (33)
Concept
The formula gives (16+18+9-6-2-3+1=33). In three sets, do not forget to add the final common part.
Why this answer is correct
The correct answer is B. (33). The formula gives (16+18+9-6-2-3+1=33). In three sets, do not forget to add the final common part.
Exam Tip
सूत्र से (16+18+9-6-2-3+1=33) मिलता है। तीन समुच्चयों में अंतिम साझा भाग जोड़ना न भूलें।
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