यदि (\frac{n!}{(n-3)!}=210) है तो (n) का मान क्या है?

If (\frac{n!}{(n-3)!}=210) then what is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).

Step 2

Why this answer is correct

The correct answer is C. (7). This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).

Step 3

Exam Tip

यह (n(n-1)(n-2)=210) देता है और \(7\times6\times5=210\) है। इसलिए (n=7) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (\frac{n!}{(n-3)!}=210) है तो (n) का मान क्या है? / If (\frac{n!}{(n-3)!}=210) then what is the value of (n)?

Correct Answer: C. (7). Explanation: यह (n(n-1)(n-2)=210) देता है और \(7\times6\times5=210\) है। इसलिए (n=7) है। / This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).

Which concept should I revise for this Mathematics MCQ?

This gives (n(n-1)(n-2)=210) and \(7\times6\times5=210\). Therefore (n=7).

What exam hint can help solve this Mathematics question?

यह (n(n-1)(n-2)=210) देता है और \(7\times6\times5=210\) है। इसलिए (n=7) है।