यदि (\frac{n!+(n-1)!}{(n-1)!}=9) हो, तो (n) का मान क्या है?

If (\frac{n!+(n-1)!}{(n-1)!}=9), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.

Step 2

Why this answer is correct

The correct answer is C. (8). The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.

Step 3

Exam Tip

भिन्न का सरल रूप (n+1) है, इसलिए (n+1=9) से (n=8)। पहले सामान्य फैक्टोरियल निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि (\frac{n!+(n-1)!}{(n-1)!}=9) हो, तो (n) का मान क्या है? / If (\frac{n!+(n-1)!}{(n-1)!}=9), what is the value of (n)?

Correct Answer: C. (8). Explanation: भिन्न का सरल रूप (n+1) है, इसलिए (n+1=9) से (n=8)। पहले सामान्य फैक्टोरियल निकालें। / The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.

Which concept should I revise for this Mathematics MCQ?

The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.

What exam hint can help solve this Mathematics question?

भिन्न का सरल रूप (n+1) है, इसलिए (n+1=9) से (n=8)। पहले सामान्य फैक्टोरियल निकालें।