यदि (\frac{n!+(n-1)!}{(n-1)!}=9) हो, तो (n) का मान क्या है?
If (\frac{n!+(n-1)!}{(n-1)!}=9), what is the value of (n)?
Explanation opens after your attempt
C. (8)
Concept
The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.
Why this answer is correct
The correct answer is C. (8). The simplified form of the fraction is (n+1), so (n+1=9) gives (n=8). First take the common factorial.
Exam Tip
भिन्न का सरल रूप (n+1) है, इसलिए (n+1=9) से (n=8)। पहले सामान्य फैक्टोरियल निकालें।
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