(\frac{(n+3)!}{(n+1)!}=110) होने पर (n) का मान क्या होगा?
If (\frac{(n+3)!}{(n+1)!}=110) then what will be the value of (n)?
Explanation opens after your attempt
B. (8)
Concept
((n+3)(n+2)=110). From \(11\times10=110\), we get (n=8).
Why this answer is correct
The correct answer is B. (8). ((n+3)(n+2)=110). From \(11\times10=110\), we get (n=8).
Exam Tip
((n+3)(n+2)=110) है। \(11\times10=110\) से (n=8) मिलता है।
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