यदि (f(x)=x+\frac{1}{x}), (x>0), तो (f) का परिसर क्या है?
If (f(x)=x+\frac{1}{x}), (x>0), what is the range of (f)?
Explanation opens after your attempt
Correct Answer
A. \([2,\infty\))
Concept
For (x>0), \(x+\frac{1}{x}\ge 2\). Equality occurs at (x=1).
Why this answer is correct
The correct answer is A. \([2,\infty\)). For (x>0), \(x+\frac{1}{x}\ge 2\). Equality occurs at (x=1).
Exam Tip
(x>0) के लिए \(x+\frac{1}{x}\ge 2\) होता है। बराबरी (x=1) पर आती है।
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